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1
JEE Main 2023 (Online) 30th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
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Benzyl isocyanide can be obtained by :

A. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Compounds Containing Nitrogen Question 54 English 1

B. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Compounds Containing Nitrogen Question 54 English 2

C. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Compounds Containing Nitrogen Question 54 English 3

D. JEE Main 2023 (Online) 30th January Morning Shift Chemistry - Compounds Containing Nitrogen Question 54 English 4

Choose the correct answer from the options given below :

A
B and C
B
A and D
C
A and B
D
Only B
2
JEE Main 2023 (Online) 29th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
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Reaction of propanamide with $$\mathrm{Br_2/KOH(aq)}$$ produces :

A
Propanenitrile
B
Propylamine
C
Ethylnitrile
D
Ethylamine
3
JEE Main 2023 (Online) 29th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The major product 'P' for the following sequence of reactions is :

JEE Main 2023 (Online) 29th January Morning Shift Chemistry - Compounds Containing Nitrogen Question 52 English

A
JEE Main 2023 (Online) 29th January Morning Shift Chemistry - Compounds Containing Nitrogen Question 52 English Option 1
B
JEE Main 2023 (Online) 29th January Morning Shift Chemistry - Compounds Containing Nitrogen Question 52 English Option 2
C
JEE Main 2023 (Online) 29th January Morning Shift Chemistry - Compounds Containing Nitrogen Question 52 English Option 3
D
JEE Main 2023 (Online) 29th January Morning Shift Chemistry - Compounds Containing Nitrogen Question 52 English Option 4
4
JEE Main 2023 (Online) 29th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List I with List II

List I List II
Reaction Reagents
(A) Hoffmann Degradation (I) $$\mathrm{Conc. KOH}$$, $$\Delta$$
(B) Clemenson reduction (II) $$\mathrm{CHCl_3,NaOH/H_3O}$$$$^ \oplus $$
(C) Cannizaro reaction (III) $$\mathrm{Br_2,NaOH}$$
(D) Reimer-Tiemann Reaction (IV) $$\mathrm{Zn-Hg/HCl}$$

Choose the correct answer from the options given below :

A
(A) - III, (B) - IV, (C) - I, (D) - II
B
(A) - II, (B) - IV, (C) - I, (D) - III
C
(A) - III, (B) - IV, (C) - II, (D) - I
D
(A) - II, (B) - I, (C) - III, (D) - IV
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