1
JEE Main 2022 (Online) 28th July Morning Shift
+4
-1

Identify the correct statement for the below given transformation.

A
$$\mathrm{A}-\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}, \mathrm{~B}-\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{2}$$, Saytzeff products
B
$$\mathrm{A}-\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}$$, B $$-\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{2}$$, Hofmann products
C
$$\mathrm{A}-\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{2}, \mathrm{~B}-\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CHCH}_{3}$$, Hofmann products
D
$$\mathrm{A}-\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{2}, \mathrm{~B}-\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CHCH}_{3}$$, Saytzeff products
2
JEE Main 2022 (Online) 27th July Evening Shift
+4
-1

An organic compound $$'\mathrm{A}'$$ contains nitrogen and chlorine. It dissolves readily in water to give a solution that turns litmus red. Titration of compound $$'\mathrm{A}'$$ with standard base indicates that the molecular weight of $$'\mathrm{A}'$$ is $$131 \pm 2$$. When a sample of $$'\mathrm{A}'$$ is treated with aq. $$\mathrm{NaOH}$$, a liquid separates which contains $$\mathrm{N}$$ but not $$\mathrm{Cl}$$. Treatment of the obtained liquid with nitrous acid followed by phenol gives orange precipitate. The compound $$'\mathrm{A}'$$ is :

A
B
C
D
3
JEE Main 2022 (Online) 27th July Morning Shift
+4
-1

Match List I with List II.

List I List II
(A) Benzenesulphonyl chloride (I) Test for primary amines
(B) Hoffmann bromamide reaction (II) Anti Saytzeff
(C) Carbylamine reaction (III) Hinsberg reagent
(D) Hoffmann orientation (IV) Known reaction of Isocyanates.

Choose the correct answer from the options given below:

A
A-IV, B-III, C-II, D-I
B
A-IV, B-II, C-I, D-III
C
A-III, B-IV, C-I, D-II
D
A-IV, B-III, C-I, D-II
4
JEE Main 2022 (Online) 26th July Evening Shift
+4
-1

The correct sequential order of the reagents for the given reaction is

A
$$\mathrm{HNO}_{2}, \mathrm{Fe} / \mathrm{H}^{+}, \mathrm{HNO}_{2}, \mathrm{KI}, \mathrm{H}_{2} \mathrm{O} / \mathrm{H}^{+}$$
B
$$\mathrm{HNO}_{2}, \mathrm{KI}, \mathrm{Fe} / \mathrm{H}^{+}, \mathrm{HNO}_{2}, \mathrm{H}_{2} \mathrm{O} /$$ warm
C
$$\mathrm{HNO}_{2}, \mathrm{KI}, \mathrm{HNO}_{2}, \mathrm{Fe} / \mathrm{H}^{+}, \mathrm{H}_{2} \mathrm{O} / \mathrm{H}^{+}$$
D
$$\mathrm{HNO}_{2}, \mathrm{Fe} / \mathrm{H}^{+}, \mathrm{KI}, \mathrm{HNO}_{2}, \mathrm{H}_{2} \mathrm{O} /$$ warm
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