JEE Main 2019 (Online) 9th April Morning Slot | Chemical Kinetics and Nuclear Chemistry Question 91 | Chemistry

JEE Main 2019 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

The given plots represent the variation of the concentration of a reactant R with time for two different reactions (i) and (ii). The respective orders of the reactions are : JEE Main 2019 (Online) 9th April Morning Slot Chemistry - Chemical Kinetics and Nuclear Chemistry Question 91 English

JEE Main 2019 (Online) 9th April Morning Slot Chemistry - Chemical Kinetics and Nuclear Chemistry Question 91 English

0,1

1,0

0,2

1,1

JEE Main 2019 (Online) 8th April Evening Slot

MCQ (Single Correct Answer)

-1

For a reaction scheme $$A\buildrel {{k_1}} \over \longrightarrow B\buildrel {{k_2}} \over \longrightarrow C$$,

if the rate of formation of B is set to be zero then the concentration of B is given by :

$${k_1}{k_2}[A]$$

$$\left( {{{{k_1}} \over {{k_2}}}} \right)[A]$$

$$({k_1} + {k_2})[A]$$

$$({k_1} - {k_2})[A]$$

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

For the reaction 2A + B $$ \to $$ C, the values of initial rate at diffrent reactant concentrations are given in the table below. The rate law for the reaction is :

[A] (mol L^-1)	[B] (mol L^-1)	Initial Rate (mol L^-1s^-1)
0.05	0.05	0.045
0.10	0.05	0.090
0.20	0.10	0.72

Rate = k[A][B]²

Rate = k[A]²[B]²

Rate = k[A]²[B]

Rate = k[A][B]

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

If solublity product of Zr₃(PO₄)₄ is denoted by K_sp and its molar solubility is denoted by S, then which of the following relation between S and K_sp is correct ?

$$S = {\left( {{{{K_{sp}}} \over {929}}} \right)^{1/9}}$$

$$S = {\left( {{{{K_{sp}}} \over {6912}}} \right)^{1/7}}$$

$$S = {\left( {{{{K_{sp}}} \over {144}}} \right)^{1/6}}$$

$$S = {\left( {{{{K_{sp}}} \over {216}}} \right)^{1/7}}$$

PREVIOUS NEXT