1
JEE Main 2024 (Online) 31st January Morning Shift
+4
-1

Integrated rate law equation for a first order gas phase reaction is given by (where $$\mathrm{P}_{\mathrm{i}}$$ is initial pressure and $$\mathrm{P}_{\mathrm{t}}$$ is total pressure at time $$t$$)

A
$$k=\frac{2.303}{t} \times \log \frac{P_i}{\left(2 P_i-P_t\right)}$$
B
$$\mathrm{k}=\frac{2.303}{\mathrm{t}} \times \log \frac{\left(2 \mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{t}}\right)}{\mathrm{P}_{\mathrm{i}}}$$
C
$$k=\frac{2.303}{t} \times \frac{P_i}{\left(2 P_i-P_t\right)}$$
D
$$\mathrm{k}=\frac{2.303}{\mathrm{t}} \times \log \frac{2 \mathrm{P}_{\mathrm{i}}}{\left(2 \mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{t}}\right)}$$
2
JEE Main 2023 (Online) 11th April Evening Shift
+4
-1

For a chemical reaction $$\mathrm{A}+\mathrm{B} \rightarrow$$ Product, the order is 1 with respect to $$\mathrm{A}$$ and $$\mathrm{B}$$.

$$\mathrm{Rate}$$
$$\mathrm{mol~L^{-1}~S^{-1}}$$
$$\mathrm{[A]}$$
$$\mathrm{mol~L^{-1}}$$
$$\mathrm{[B]}$$
$$\mathrm{mol~L^{-1}}$$
0.10 20 0.5
0.40 $$x$$ 0.5
0.80 40 $$y$$

What is the value of $$x$$ and $$y$$ ?

A
80 and 4
B
160 and 4
C
80 and 2
D
40 and 4
3
JEE Main 2023 (Online) 8th April Evening Shift
+4
-1

The correct reaction profile diagram for a positive catalyst reaction.

A
B
C
D
4
JEE Main 2023 (Online) 6th April Evening Shift
+4
-1

Consider the following reaction that goes from A to B in three steps as shown below:

Choose the correct option

A
B
C
D
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