1
JEE Main 2023 (Online) 24th January Evening Shift
+4
-1 A student has studied the decomposition of a gas AB$$_3$$ at 25$$^\circ$$C. He obtained the following data.

p (mm Hg) 50 100 200 400
relative t$$_{1/2}$$ (s) 4 2 1 0.5

The order of the reaction is

A
2
B
0.5
C
1
D
0 (zero)
2
JEE Main 2022 (Online) 26th July Evening Shift
+4
-1 At $$30^{\circ} \mathrm{C}$$, the half life for the decomposition of $$\mathrm{AB}_{2}$$ is $$200 \mathrm{~s}$$ and is independent of the initial concentration of $$\mathrm{AB}_{2}$$. The time required for $$80 \%$$ of the $$\mathrm{AB}_{2}$$ to decompose is

Given: $$\log 2=0.30$$ $$\quad \log 3=0.48$$

A
200 s
B
323 s
C
467 s
D
532 s
3
JEE Main 2022 (Online) 25th July Evening Shift
+4
-1 $${K_{{a_1}}}$$, $${K_{{a_2}}}$$ and $${K_{{a_3}}}$$ are the respective ionization constants for the following reactions (a), (b) and (c).

(a) $${H_2}{C_2}{O_4} \mathbin{\lower.3ex\hbox{\buildrel\textstyle\rightarrow\over {\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}}} {H^ + } + H{C_2}O_4^ -$$

(b) $$H{C_2}O_4^ - \mathbin{\lower.3ex\hbox{\buildrel\textstyle\rightarrow\over {\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}}} {H^ + } + H{C_2}O_4^{2 - }$$

(c) $${H_2}{C_2}O_4^{} \mathbin{\lower.3ex\hbox{\buildrel\textstyle\rightarrow\over {\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}}} 2{H^ + } + {C_2}O_4^{2 - }$$

The relationship between $${K_{{a_1}}}$$, $${K_{{a_2}}}$$ and $${K_{{a_3}}}$$ is given as

A
$${K_{{a_3}}}$$ $$=$$ $${K_{{a_1}}}$$ $$+$$ $${K_{{a_2}}}$$
B
$${K_{{a_3}}}$$ $$=$$ $${K_{{a_1}}}$$ $$-$$ $${K_{{a_2}}}$$
C
$${K_{{a_3}}}$$ $$=$$ $${K_{{a_1}}}$$ $$/$$ $${K_{{a_2}}}$$
D
$${K_{{a_3}}}$$ $$=$$ $${K_{{a_1}}}$$ $$\times$$ $${K_{{a_2}}}$$
4
JEE Main 2022 (Online) 30th June Morning Shift
+4
-1

The equilibrium constant for the reversible reaction

2A(g) $$\rightleftharpoons$$ 2B(g) + C(g) is K1

$${3 \over 2}$$A(g) $$\rightleftharpoons$$ $${3 \over 2}$$B(g) + $${3 \over 4}$$C(g) is K2.

K1 and K2 are related as :

A
$${K_1} = \sqrt {{K_2}}$$
B
$${K_2} = \sqrt {{K_1}}$$
C
$${K_2} = K_1^{3/4}$$
D
$${K_1} = K_2^{3/4}$$
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