1
JEE Main 2026 (Online) 23rd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Which statements are NOT TRUE about $\mathrm{XeO}_2 \mathrm{~F}_2$?

A. It has a see-saw shape.

B. Xe has 5 electron pairs in its valence shell in $\mathrm{XeO}_2 \mathrm{~F}_2$.

C. The $\mathrm{O}-\mathrm{Xe}-\mathrm{O}$ bond angle is close to $180^{\circ}$.

D. The $\mathrm{F}-\mathrm{Xe}-\mathrm{F}$ bond angle is close to $180^{\circ}$.

E. Xe has 16 valence electrons in $\mathrm{XeO}_2 \mathrm{~F}_2$.

Choose the correct answer from the options given below :

A

B, D and E Only

B

B and D Only

C

B, C and E Only

D

A and D Only

2
JEE Main 2026 (Online) 23rd January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Identify the molecule $(X)$ with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among $\mathrm{HNO}_3, \mathrm{H}_2 \mathrm{SO}_4, \mathrm{NF}_3$ and $\mathrm{O}_3$. Choose the correct bond angle made by the central atom of the molecule $(X)$.

A

$107^{\circ}$

B

$102^{\circ}$

C

$120^{\circ}$

D

$116^{\circ}$

3
JEE Main 2026 (Online) 22nd January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Among $\mathrm{H}_2 \mathrm{~S}, \mathrm{H}_2 \mathrm{O}, \mathrm{NF}_3, \mathrm{NH}_3$ and $\mathrm{CHCl}_3$, identify the molecule $(\mathrm{X})$ with lowest dipole moment value. The number of lone pairs of electrons present on the central atom of the molecule $(X)$ is :

A

3

B

2

C

0

D

1

4
JEE Main 2026 (Online) 22nd January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Two p-block elements X and Y form fluorides of the type $\mathrm{EF}_3$. The fluoride compound $\mathrm{XF}_3$ is a Lewis acid and $\mathrm{YF}_3$ is a Lewis base. The hybridizations of the central atoms of $\mathrm{XF}_3$ and $\mathrm{YF}_3$ respectively are

A

$\mathrm{sp}^2$ and $\mathrm{sp}^3$

B

Both $\mathrm{sp}^3$

C

Both $\mathrm{sp}^2$

D

$\mathrm{sp}^3$ and $\mathrm{sp}^2$

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