JEE Main 2025 (Online) 23rd January Morning Shift | Chemical Bonding & Molecular Structure Question 8 | Chemistry

	List - I (Classification of molecules based on octet rule)		List - II (Example)
(A)	Molecules obeying octet rule	(I)	$\mathrm{NO}, \mathrm{NO}_2$
(B)	Molecules with incomplete octet	(II)	$\mathrm{BCl}_3, \mathrm{AlCl}_3$
(C)	Molecules with incomplete octet with odd electron	(III)	$\mathrm{H}_2 \mathrm{SO}_4, \mathrm{PCl}_5$
(D)	Molecules with expanded octet	(IV)	$\mathrm{CCl}_4, \mathrm{CO}_2$

Choose the correct answer from the options given below:

A-IV, B-I, C-III, D-II

A-II, B-IV, C-III, D-I

A-IV, B-II, C-I, D-III

A-III, B-II, C-I, D-IV

JEE Main 2025 (Online) 22nd January Evening Shift

MCQ (Single Correct Answer)

-1

Arrange the following compounds in increasing order of their dipole moment :

$\mathrm{HBr}, \mathrm{H}_2 \mathrm{~S}, \mathrm{NF}_3$ and $\mathrm{CHCl}_3$

$\mathrm{HBr}<\mathrm{H}_2 \mathrm{~S}<\mathrm{NF}_3<\mathrm{CHCl}_3$

$\mathrm{H}_2 \mathrm{~S}<\mathrm{HBr}<\mathrm{NF}_3<\mathrm{CHCl}_3$

$\mathrm{NF}_3<\mathrm{HBr}<\mathrm{H}_2 \mathrm{~S}<\mathrm{CHCl}_3$

$\mathrm{CHCl}_3<\mathrm{NF}_3<\mathrm{HBr}<\mathrm{H}_2 \mathrm{S}$

JEE Main 2024 (Online) 9th April Evening Shift

MCQ (Single Correct Answer)

-1

The correct increasing order for bond angles among $$\mathrm{BF}_3, \mathrm{PF}_3$$ and $$\mathrm{ClF}_3$$ is :

$$\mathrm{BF}_3=\mathrm{PF}_3<\mathrm{ClF}_3$$

$$\mathrm{BF}_3<\mathrm{PF}_3<\mathrm{ClF}_3$$

$$\mathrm{ClF}_3<\mathrm{PF}_3<\mathrm{BF}_3$$

$$\mathrm{PF}_3<\mathrm{BF}_3<\mathrm{ClF}_3$$