Bromine trifluoride autoionizes to form $\mathrm{BrF}_2^{\oplus}$ and $\mathrm{BrF}_4^{\ominus}$. The shapes of the cation and anion are respectively $\_\_\_\_$ and $\_\_\_\_$ .

Given below are two statements :

Statement I : The number of compounds among $\mathrm{SO}_2, \mathrm{SO}_3, \mathrm{SF}_4, \mathrm{SF}_6$ and $\mathrm{H}_2 \mathrm{~S}$ in which sulphur does not obey the Octet rule is 3 .

Statement II : Among $\left[\mathrm{H}_2 \mathrm{O}, \mathrm{ClF}_3, \mathrm{SF}_4\right],\left[\mathrm{NH}_3, \mathrm{BrF}_5, \mathrm{SF}_4\right],\left[\mathrm{BrF}_5, \mathrm{ClF}_3, \mathrm{XeF}_4\right]$ and [ $\mathrm{XeF}_4, \mathrm{ClF}_3, \mathrm{H}_2 \mathrm{O}$ ], the number of sets in which all the molecules have one lone pair of electrons on the central atom is 1 .

In the light of the above statements, choose the correct answer from the options given below :

Given below are two statements :

Statement I : $\mathrm{F}_2 \mathrm{O}<\mathrm{H}_2 \mathrm{O}<\mathrm{Cl}_2 \mathrm{O}$ is the correct trend in terms of bond angle.

Statement II : $\mathrm{SiF}_4, \mathrm{SnF}_4$ and $\mathrm{PbF}_4$ are ionic in nature.

In the light of the above statements, choose the correct answer from the options given below :

The pairs among

$\mathrm{A}=\left[\mathrm{SO}_3^{2-}, \mathrm{CO}_3^{2-}\right], \mathrm{B}=\left[\mathrm{O}_2^{2-}, \mathrm{F}_2\right], \mathrm{C}=\left[\mathrm{CN}^{-}, \mathrm{CO}\right], \mathrm{D}=\left[\mathrm{NH}_3, \mathrm{H}_3 \mathrm{O}^{+}\right]$and $\mathrm{E}=\left[\mathrm{MnO}_4^{2-}, \mathrm{CrO}_4^{2-}\right]$ that do not have similar Lewis dot structure are