Match List I with List II
LIST I Oxide |
LIST II Type of bond |
||
---|---|---|---|
A. | $$\mathrm{N_2O_4}$$ | I. | 1 N = O bond |
B. | $$\mathrm{NO_2}$$ | II. | 1 N $$-$$ O $$-$$ N bond |
C. | $$\mathrm{N_2O_5}$$ | III. | 1 N $$-$$ N bond |
D. | $$\mathrm{N_2O}$$ | IV. | 1 N=N / N $$\equiv$$ N bond |
Choose the correct answer from the options given below:
$$\mathrm{O}-\mathrm{O}$$ bond length in $$\mathrm{H}_{2} \mathrm{O}_{2}$$ is $$\underline{\mathrm{X}}$$ than the $$\mathrm{O}-\mathrm{O}$$ bond length in $$\mathrm{F}_{2} \mathrm{O}_{2}$$. The $$\mathrm{O}-\mathrm{H}$$ bond length in $$\mathrm{H}_{2} \mathrm{O}_{2}$$ is $$\underline{Y}$$ than that of the $$\mathrm{O}-\mathrm{F}$$ bond in $$\mathrm{F}_{2} \mathrm{O}_{2}$$.
Choose the correct option for $$\underline{X}$$ and $$\underline{Y}$$ from those given below :
Match List I with List II
List I | List II | ||
---|---|---|---|
A. | $$\mathrm{XeF_4}$$ | I. | See-saw |
B. | $$\mathrm{SF_4}$$ | II. | Square-planar |
C. | $$\mathrm{NH_{4}^{+}}$$ | III. | Bent T-shaped |
D. | $$\mathrm{BrF_3}$$ | IV. | Tetrahedral |
Choose the correct answer from the options given below :
For $$\mathrm{OF}_{2}$$ molecule consider the following :
A. Number of lone pairs on oxygen is 2 .
B. FOF angle is less than $$104.5^{\circ}$$.
C. Oxidation state of $$\mathrm{O}$$ is $$-2$$.
D. Molecule is bent '$$\mathrm{V}$$' shaped.
E. Molecular geometry is linear.
correct options are: