JEE Main 2024 (Online) 6th April Morning Shift | Chemical Bonding & Molecular Structure Question 12 | Chemistry

1

JEE Main 2024 (Online) 6th April Morning Shift

MCQ (Single Correct Answer)

+4

-1

Match List I with List II

	LIST I (Compound/Species)		LIST II (Shape/Geometry)
A.	$$\mathrm{SF_4}$$	I.	Tetrahedral
B.	$$\mathrm{BrF_3}$$	II.	Pyramidal
C.	$$\mathrm{BrO_3^-}$$	III.	See saw
D.	$$\mathrm{NH_4^+}$$	IV.	Bent T-Shape

Choose the correct answer from the options given below:

A

A-III, B-II, C-IV, D-I

B

A-III, B-IV, C-II, D-I

C

A-II, B-IV, C-III, D-I

D

A-II, B-III, C-I, D-IV

2

JEE Main 2024 (Online) 6th April Morning Shift

MCQ (Single Correct Answer)

+4

-1

Match List I with List II

	LIST I (Molecule/Species)		LIST II (Property/Shape)
A.	$$\mathrm{SO_2Cl_2}$$	I.	Paramagnetic
B.	$$\mathrm{NO}$$	II.	Diamagnetic
C.	$$\mathrm{NO_2^-}$$	III.	Tetrahedral
D.	$$\mathrm{I_3^-}$$	IV.	Linear

Choose the correct answer from the options given below:

A

A-II, B-III, C-I, D-IV

B

A-III, B-I, C-II, D-IV

C

A-IV, B-I, C-III, D-II

D

A-III, B-IV, C-II, D-I

3

JEE Main 2024 (Online) 5th April Evening Shift

MCQ (Single Correct Answer)

+4

-1

Match List I with List II.

	LIST I		LIST II
A.	$$ \mathrm{ICl} $$	I.	T - shape
B.	$$ \mathrm{ICl}_3 $$	II.	Square pyramidal
C.	$$ \mathrm{ClF}_5 $$	III.	Pentagonal bipyramidal
D.	$$ \mathrm{IF}_7 $$	IV.	Linear

Choose the correct answer from the options given below :

A

(A)-(I), (B)-(IV), (C)-(III), (D)-(II)

B

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

C

(A)-(I), (B)-(III), (C)-(II), (D)-(IV)

D

(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

4

JEE Main 2024 (Online) 5th April Evening Shift

MCQ (Single Correct Answer)

+4

-1

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : $$\mathrm{NH}_3$$ and $$\mathrm{NF}_3$$ molecule have pyramidal shape with a lone pair of electrons on nitrogen atom. The resultant dipole moment of $$\mathrm{NH}_3$$ is greater than that of $$\mathrm{NF}_3$$.

Reason (R) : In $$\mathrm{NH}_3$$, the orbital dipole due to lone pair is in the same direction as the resultant dipole moment of the $$\mathrm{N}-\mathrm{H}$$ bonds. $$\mathrm{F}$$ is the most electronegative element.

In the light of the above statements, choose the correct answer from the options given below :

A

(A) is false but (R) is true

B

(A) is true but (R) is false

C

Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

D

Both (A) and (R) are true and (R) is the correct explanation of (A)