JEE Main 2023 (Online) 31st January Morning Shift | d and f Block Elements Question 44 | Chemistry | JEE Main - ExamSIDE.com

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1

JEE Main 2023 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

+4

-1

When $$\mathrm{Cu}^{2+}$$ ion is treated with $$\mathrm{KI}$$, a white precipitate, $$\mathrm{X}$$ appears in solution. The solution is titrated with sodium thiosulphate, the compound $$\mathrm{Y}$$ is formed. $$\mathrm{X}$$ and $$\mathrm{Y}$$ respectively are :

A

$$\mathrm{X=CuI_2}$$	$$\mathrm{Y=Na_2S_4O_6}$$

B

$$\mathrm{X=Cu_2I_2}$$	$$\mathrm{Y=Na_2S_4O_6}$$

C

$$\mathrm{X=CuI_2}$$	$$\mathrm{Y=Na_2S_2O_3}$$

D

$$\mathrm{X=Cu_2I_2}$$	$$\mathrm{Y=Na_2S_4O_5}$$

2

JEE Main 2023 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

+4

-1

$$\mathrm{Nd^{2+}}$$ = __________

A

$$\mathrm{4f^4 6s^2}$$

B

$$\mathrm{4f^3}$$

C

$$\mathrm{4f^4}$$

D

$$\mathrm{4f^2 6s^2}$$

3

JEE Main 2023 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

+4

-1

The correct order of basicity of oxides of vanadium is :

A

$$\mathrm{V_2O_3 > V_2O_5 > V_2O_4}$$

B

$$\mathrm{V_2O_3 > V_2O_4 > V_2O_5}$$

C

$$\mathrm{V_2O_5 > V_2O_4 > V_2O_3}$$

D

$$\mathrm{V_2O_4 > V_2O_3 > V_2O_5}$$

4

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

+4

-1

Formulae for Nessler's reagent is :

A

$\mathrm{KHgI}_3$

B

$\mathrm{HgI}_2$

C

$\mathrm{KHg}_2 \mathrm{I}_2$

D

$\mathrm{K}_2 \mathrm{HgI}_4$

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