JEE Main 2025 (Online) 24th January Morning Shift | d and f Block Elements Question 34 | Chemistry

Preparation of potassium permanganate from $\mathrm{MnO}_2$ involves two step process in which the 1st step is a reaction with KOH and $\mathrm{KNO}_3$ to produce

$\mathrm{K}_3 \mathrm{MnO}_4$

$\mathrm{K}_4\left[\mathrm{Mn}(\mathrm{OH})_6\right]$

$\mathrm{K}_2 \mathrm{MnO}_4$

$\mathrm{KMnO}_4$

JEE Main 2025 (Online) 24th January Morning Shift

MCQ (Single Correct Answer)

-1

Which of the following ions is the strongest oxidizing agent? (Atomic Number of $\mathrm{Ce}=58, \mathrm{Eu}=63, \mathrm{~Tb}=65, \mathrm{Lu}=71$)

$\mathrm{Lu}^{3+}$

$\mathrm{Eu}^{2+}$

$\mathrm{Tb}^{4+}$

$\mathrm{Ce}^{3+}$

JEE Main 2025 (Online) 23rd January Evening Shift

MCQ (Single Correct Answer)

-1

Match List - I with List - II

	List - I		List - II
(A)	Bronze	(I)	Cu, Ni
(B)	Brass	(II)	Fe, Cr, Ni, C
(C)	UK silver coin	(III)	Cu, Zn
(D)	Stainless steel	(IV)	Cu, Sn

Choose the correct answer from the options given below :

(A)-(IV), (B)-(II), (C)-(III), (D)-(I)

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

JEE Main 2025 (Online) 23rd January Evening Shift

MCQ (Single Correct Answer)

-1

Consider the following reactions

$$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 \xrightarrow[-\mathrm{H}_2 \mathrm{O}]{\mathrm{KOH}}[\mathrm{~A}] \xrightarrow[-\mathrm{H}_2 \mathrm{O}]{\mathrm{H}_2 \mathrm{SO}_4}[\mathrm{~B}]+\mathrm{K}_2 \mathrm{SO}_4$$

The products $[A]$ and $[B]$, respectively are :

$\mathrm{K}_2 \mathrm{Cr}(\mathrm{OH})_6$ and $\mathrm{Cr}_2 \mathrm{O}_3$

$\mathrm{K}_2 \mathrm{CrO}_4$ and $\mathrm{Cr}_2 \mathrm{O}_3$

$\mathrm{K}_2 \mathrm{CrO}_4$ and $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$

$\mathrm{K}_2 \mathrm{CrO}_4$ and $\mathrm{CrO}$

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