1
JEE Main 2024 (Online) 27th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

$$\mathrm{NaCl}$$ reacts with conc. $$\mathrm{H}_2 \mathrm{SO}_4$$ and $$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$$ to give reddish fumes (B), which react with $$\mathrm{NaOH}$$ to give yellow solution (C). (B) and (C) respectively are ;

A
$$\mathrm{CrO}_2 \mathrm{Cl}_2, \mathrm{Na}_2 \mathrm{CrO}_4$$
B
$$\mathrm{Na}_2 \mathrm{CrO}_4, \mathrm{CrO}_2 \mathrm{Cl}_2$$
C
$$\mathrm{CrO}_2 \mathrm{Cl}_2, \mathrm{KHSO}_4$$
D
$$\mathrm{CrO}_2 \mathrm{Cl}_2, \mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7$$
2
JEE Main 2024 (Online) 27th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The electronic configuration for Neodymium is:

[Atomic Number for Neodymium 60]

A
$$[\mathrm{Xe}] 4 \mathrm{f}^4 6 \mathrm{~s}^2$$
B
$$[\mathrm{Xe}] 5 \mathrm{f}^4 7 \mathrm{~s}^2$$
C
$$[\mathrm{Xe}] 4 \mathrm{f}^6 6 \mathrm{~s}^2$$
D
$$[\mathrm{Xe}] 4 \mathrm{f}^1 5 \mathrm{~d}^1 6 \mathrm{~s}^2$$
3
JEE Main 2023 (Online) 13th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The pair of lanthanides in which both elements have high third - ionization energy is :

A
Dy, Gd
B
Lu, Yb
C
Eu, Yb
D
Eu, Gd
4
JEE Main 2023 (Online) 12th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statement: one is labelled as Assertion $$\mathbf{A}$$ and the other is labelled as Reason $$\mathbf{R}$$

Assertion A: $$5 \mathrm{f}$$ electrons can participate in bonding to a far greater extent than $$4 \mathrm{f}$$ electrons

Reason R: $$5 \mathrm{f}$$ orbitals are not as buried as $$4 \mathrm{f}$$ orbitals

In the light of the above statements, choose the correct answer from the options given below

A
Both A and R are true and R is the correct explanation of A
B
Both A and R are true but R is NOT the correct explanation of A
C
A is true but R is false
D
A is false but R is true
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