1
JEE Main 2026 (Online) 21st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A spherical body of radius $r$ and density $\sigma$ falls freely through a viscous liquid having density $\rho$ and viscosity $\eta$ and attains a terminal velocity $v_0$. Estimated maximum error in the quantity $\eta$ is : (Ignore errors associated with $\sigma$, $\rho$ and $g$, gravitational acceleration)

A

$2 \left[ \frac{\Delta r}{r} - \frac{\Delta v_0}{v_0} \right]$

B

$2 \left[ \frac{\Delta r}{r} + \frac{\Delta v_0}{v_0} \right]$

C

$\frac{2 \Delta r}{r} + \frac{\Delta v_0}{v_0}$

D

$2 \frac{\Delta r}{r} - \frac{\Delta v_0}{v_0}$

2
JEE Main 2026 (Online) 21st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Keeping the significant figures in view, the sum of the physical quantities 52.01 m, 153.2 m and 0.123 m is :

A

205.3 m

B

205 m

C

205.333 m

D

205.33 m

3
JEE Main 2026 (Online) 21st January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

In an experiment the values of two spring constants were measured as $k_1=(10 \pm 0.2) \mathrm{N} / \mathrm{m}$ and $k_2=(20 \pm 0.3) \mathrm{N} / \mathrm{m}$. If these springs are connected in parallel, then the percentage error in equivalent spring constant is :

A

1.33%

B

$2.67 \%$

C

1.67%

D

$2.33 \%$

4
JEE Main 2026 (Online) 21st January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider a modified Bernoulli equation.

$$ \left(\mathrm{P}+\frac{A}{B t^2}\right)+\rho g(h+B t)+\frac{1}{2} \rho V^2=\text { constant } $$

If $t$ has the dimension of time then the dimensions of $A$ and $B$ are $\_\_\_\_$ , $\_\_\_\_$ respectively.

A

$\left[\mathrm{ML}^0 \mathrm{~T}^{-1}\right]$ and $\left[\mathrm{M}^0 \mathrm{LT}\right]$

B

$\left[\mathrm{ML}^0 \mathrm{~T}^{-2}\right]$ and $\left[\mathrm{M}^0 \mathrm{LT}^{-1}\right]$

C

$\left[\mathrm{ML}^0 \mathrm{~T}^{-2}\right]$ and $\left[\mathrm{M}^0 \mathrm{LT}^{-2}\right]$

D

$\left[\mathrm{ML}^0 \mathrm{~T}^{-1}\right]$ and $\left[\mathrm{M}^0 \mathrm{LT}^{-1}\right]$

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