1
JEE Main 2021 (Online) 25th July Evening Shift
+4
-1
The force is given in terms of time t and displacement x by the equation

F = A cos Bx + C sin Dt

The dimensional formula of $${{AD} \over B}$$ is :
A
$$[{M^0}L{T^{ - 1}}]$$
B
$$[M{L^2}{T^{ - 3}}]$$
C
$$[{M^1}{L^1}{T^{ - 2}}]$$
D
$$[{M^2}{L^2}{T^{ - 3}}]$$
2
JEE Main 2021 (Online) 20th July Evening Shift
+4
-1
If time (t), velocity (v), and angular momentum (l) are taken as the fundamental units. Then the dimension of mass (m) in terms of t, v and l is :
A
$$[{t^{ - 1}}{v^1}{l^{ - 2}}]$$
B
$$[{t^1}{v^2}{l^{ - 1}}]$$
C
$$[{t^{ - 2}}{v^{ - 1}}{l^1}]$$
D
$$[{t^{ - 1}}{v^{ - 2}}{l^1}]$$
3
JEE Main 2021 (Online) 17th March Morning Shift
+4
-1
The vernier scale used for measurement has a positive zero error of 0.2 mm. If while taking a measurement it was noted that '0' on the vernier scale lies between 8.5 cm and 8.6 cm, vernier coincidence is 6, then the correct value of measurement is ___________ cm. (least count = 0.01 cm)
A
8.58 cm
B
8.54 cm
C
8.56 cm
D
8.36 cm
4
JEE Main 2021 (Online) 16th March Evening Shift
+4
-1
In order to determine the Young's Modulus of a wire of radius 0.2 cm (measured using a scale of least count = 0.001 cm) and length 1m (measured using a scale of least count = 1 mm), a weight of mass 1 kg (measured using a scale of least count = 1 g) was hanged to get the elongation of 0.5 cm (measured using a scale of least count 0.001 cm). What will be the fractional error in the value of Young's Modulus determined by this experiment?
A
0.14%
B
9%
C
1.4%
D
0.9%
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