JEE Main 2021 (Online) 17th March Morning Shift | Units & Measurements Question 102 | Physics

The vernier scale used for measurement has a positive zero error of 0.2 mm. If while taking a measurement it was noted that '0' on the vernier scale lies between 8.5 cm and 8.6 cm, vernier coincidence is 6, then the correct value of measurement is ___________ cm. (least count = 0.01 cm)

8.58 cm

8.54 cm

8.56 cm

8.36 cm

JEE Main 2021 (Online) 16th March Evening Shift

MCQ (Single Correct Answer)

-1

In order to determine the Young's Modulus of a wire of radius 0.2 cm (measured using a scale of least count = 0.001 cm) and length 1m (measured using a scale of least count = 1 mm), a weight of mass 1 kg (measured using a scale of least count = 1 g) was hanged to get the elongation of 0.5 cm (measured using a scale of least count 0.001 cm). What will be the fractional error in the value of Young's Modulus determined by this experiment?

0.14%

1.4%

0.9%

JEE Main 2021 (Online) 16th March Morning Shift

MCQ (Single Correct Answer)

-1

One main scale division of a vernier callipers is 'a' cm and n^th division of the vernier scale coincide with (n $$-$$ 1)^th division of the main scale. The least count of the callipers in mm is :

$${{10a} \over n}$$

$${{10na} \over {(n - 1)}}$$

$$\left( {{{n - 1} \over {10n}}} \right)a$$

$${{10a} \over {(n - 1)}}$$

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

If 'C' and 'V' represent capacity and voltage respectively then what are the dimensions of $$\lambda$$ where C/V = $$\lambda$$ ?

$$[{M^{ - 3}}{L^{ - 4}}{I^3}{T^7}]$$

$$[{M^{ - 2}}{L^{ - 3}}{I^2}{T^6}]$$

$$[{M^{ - 2}}{L^{ - 4}}{I^3}{T^7}]$$

$$[{M^{ - 1}}{L^{ - 3}}{I^{ - 2}}{T^{ - 7}}]$$