1
JEE Main 2021 (Online) 26th August Morning Shift
+4
-1
In a Screw Gauge, fifth division of the circular scale coincides with the reference line when the ratchet is closed. There are 50 divisions on the circular scale, and the main scale moves by 0.5 mm on a complete rotation. For a particular observation the reading on the main scale is 5 mm and the 20th division of the circular scale coincides with reference line. Calculate the true reading.
A
5.00 mm
B
5.25 mm
C
5.15 mm
D
5.20 mm
2
JEE Main 2021 (Online) 26th August Morning Shift
+4
-1
If E, L, M and G denote the quantities as energy, angular momentum, mass and constant of gravitation respectively, then the dimensions of P in the formula P = EL2M$$-$$5G$$-$$2 are :
A
[M0 L1 T0]
B
[M$$-$$1 L$$-$$1 T2]
C
[M1 L1 T$$-$$2]
D
[M0 L0 T0]
3
JEE Main 2021 (Online) 27th July Evening Shift
+4
-1
A physical quantity 'y' is represented by the formula $$y = {m^2}{r^{ - 4}}{g^x}{l^{ - {3 \over 2}}}$$

If the percentage errors found in y, m, r, l and g are 18, 1, 0.5, 4 and p respectively, then find the value of x and p.
A
5 and $$\pm$$2
B
4 and $$\pm$$3
C
$${{16} \over 3}$$ and $$\pm {3 \over 2}$$
D
8 and $$\pm$$ 2
4
JEE Main 2021 (Online) 27th July Morning Shift
+4
-1
Assertion A : If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm.

Reason R :

Least Count = $${{Pitch} \over {Total\,divisions\,on\,circular\,scale}}$$

In the light of the above statements, choose the most appropriate answer from the options given below :
A
A is not correct but R is correct.
B
Both A and R are correct and R is the correct explanation of A.
C
A is correct but R is not correct.
D
Both A and R are correct and R is NOT the correct explanation of A.
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