1
JEE Main 2020 (Online) 3rd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Using screw gauge of pitch 0.1 cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as
A
2.123 cm
B
2.124 cm
C
2.125 cm
D
2.121 cm
2
JEE Main 2020 (Online) 2nd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If momentum (P), area (A) and time (T) are taken to be the fundamental quantities then the dimensional formula for energy is
A
[P2AT–2]
B
$$\left[ {{P^{{1 \over 2}}}A{T^{ - 1}}} \right]$$
C
$$\left[ {P{A^{{1 \over 2}}}{T^{ - 1}}} \right]$$
D
[PA–1T–2]
3
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The least count of the main scale of a vernier callipers is 1 mm. Its vernier scale is divided into 10 divisions and coincide with 9 divisions of the main scale. When jaws are touching each other, the 7th division of vernier scale coincides with a division of main scale and the zero of vernier scale is lying right side of the zero of main scale. When this vernier is used to measure length of a cylinder the zero of the vernier scale between 3.1 cm and 3.2 cm and 4th VSD coincides with a main scale division. The length of the cylinder is : (VSD is vernier scale division)
A
3.21 cm
B
2.99 cm
C
3.07 cm
D
3.2 cm
4
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If speed V, area A and force F are chosen as fundamental units, then the dimension of Young’s modulus will be
A
FA–1V0
B
FA2V–1
C
FA2V–2
D
FA2V–3
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