JEE Main 2026 (Online) 22nd January Morning Shift | Units & Measurements Question 26 | Physics

List-I		List-II
A.	Spring constant	I.	$M L^{2} T^{- 2} K^{- 1}$
B.	Thermal conductivity	II.	${ML}^{0} T^{- 2}$
C.	Boltzmann constant	III.	$M L^{2} T^{- 3} A^{- 2}$
D.	Inductive reactance	IV.	$M L T^{- 3} K^{- 1}$

Choose the correct answer from the options given below:

A-III, B-II, C-IV, D-I

A-I, B-IV, C-II, D-III

A-II, B-I, C-IV, D-III

A-II, B-IV, C-I, D-III

JEE Main 2026 (Online) 21st January Evening Shift

MCQ (Single Correct Answer)

-1

A spherical body of radius $r$ and density $\sigma$ falls freely through a viscous liquid having density $\rho$ and viscosity $\eta$ and attains a terminal velocity $v_0$. Estimated maximum error in the quantity $\eta$ is : (Ignore errors associated with $\sigma$, $\rho$ and $g$, gravitational acceleration)

$2 \left[ \frac{\Delta r}{r} - \frac{\Delta v_0}{v_0} \right]$

$2 \left[ \frac{\Delta r}{r} + \frac{\Delta v_0}{v_0} \right]$

$\frac{2 \Delta r}{r} + \frac{\Delta v_0}{v_0}$

$2 \frac{\Delta r}{r} - \frac{\Delta v_0}{v_0}$

JEE Main 2026 (Online) 21st January Evening Shift

MCQ (Single Correct Answer)

-1

Keeping the significant figures in view, the sum of the physical quantities 52.01 m, 153.2 m and 0.123 m is :

205.3 m

205 m

205.333 m

205.33 m

JEE Main 2026 (Online) 21st January Morning Shift

MCQ (Single Correct Answer)

-1

In an experiment the values of two spring constants were measured as $k_1=(10 \pm 0.2) \mathrm{N} / \mathrm{m}$ and $k_2=(20 \pm 0.3) \mathrm{N} / \mathrm{m}$. If these springs are connected in parallel, then the percentage error in equivalent spring constant is :

1.33%

$2.67 \%$

1.67%

$2.33 \%$

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