1
JEE Main 2021 (Online) 25th February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Match List - I with List - II :

List I List II
(a) h (Planck's constant) (i) $$[ML{T^{ - 1}}]$$
(b) E (kinetic energy) (ii) $$[M{L^2}{T^{ - 1}}]$$
(c) V (electric potential) (iii) $$[M{L^2}{T^{ - 2}}]$$
(d) P (linear momentum) (iv) $$[M{L^2}{I^{ - 1}}{T^{ - 3}}]$$


Choose the correct answer from the options given below :
A
(a) $$ \to $$ (ii), (b) $$ \to $$ (iii), (c) $$ \to $$ (iv), (d) $$ \to $$ (i)
B
(a) $$ \to $$ (i), (b) $$ \to $$ (ii), (c) $$ \to $$ (iv), (d) $$ \to $$ (iii)
C
(a) $$ \to $$ (iii), (b) $$ \to $$ (ii), (c) $$ \to $$ (iv), (d) $$ \to $$ (i)
D
(a) $$ \to $$ (iii), (b) $$ \to $$ (iv), (c) $$ \to $$ (ii), (d) $$ \to $$ (i)
2
JEE Main 2021 (Online) 25th February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
The pitch of the screw gauge is 1 mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while 72nd division on circular scale coincides with the reference line. The radius of the wire is :
A
1.80 mm
B
0.90 mm
C
0.82 mm
D
1.64 mm
3
JEE Main 2021 (Online) 24th February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
The work done by a gas molecule in an isolated system is

given by, $$W = \alpha {\beta ^2}{e^{ - {{{x^2}} \over {\alpha kT}}}}$$, where x is the displacement, k is the Boltzmann constant and T is the temperature. $$\alpha$$ and $$\beta$$ are constants. Then the dimensions of $$\beta$$ will be :
A
$$[{M^0}L{T^0}]$$
B
$$[M{L^2}{T^{ - 2}}]$$
C
$$[ML{T^{ - 2}}]$$
D
$$[{M^2}L{T^2}]$$
4
JEE Main 2020 (Online) 6th September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A student measuring the diameter of a pencil of circular cross-section with the help of a vernier scale records the following four readings 5.50 mm, 5.55 mm, 5.45 mm, 5.65 mm. The average of these four readings is 5.5375 mm and the standard deviation of the data is 0.07395 mm. The average diameter
of the pencil should therefore be recorded as :
A
(5.54 $$ \pm $$ 0.07) mm
B
(5.5375 $$ \pm $$ 0.0740) mm
C
(5.5375 $$ \pm $$ 0.0739) mm
D
(5.538 $$ \pm $$ 0.074) mm
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