JEE Main 2024 (Online) 4th April Evening Shift | Units & Measurements Question 17 | Physics

Applying the principle of homogeneity of dimensions, determine which one is correct, where $$T$$ is time period, $$G$$ is gravitational constant, $$M$$ is mass, $$r$$ is radius of orbit.

$$T^2=\frac{4 \pi^2 r}{G M^2}$$

$$T^2=4 \pi^2 r^3$$

$$T^2=\frac{4 \pi^2 r^3}{G M}$$

$$T^2=\frac{4 \pi^2 r^2}{G M}$$

JEE Main 2024 (Online) 4th April Morning Shift

MCQ (Single Correct Answer)

-1

The equation of stationary wave is :

$$y=2 \mathrm{a} \sin \left(\frac{2 \pi \mathrm{nt}}{\lambda}\right) \cos \left(\frac{2 \pi x}{\lambda}\right) \text {. }$$

Which of the following is NOT correct :

The dimensions of $$\mathrm{nt}$$ is [L]

The dimensions of $$n$$ is $$[\mathrm{LT}^{-1}]$$

The dimensions of $$x$$ is [L]

The dimensions of $$n / \lambda$$ is [T]

JEE Main 2024 (Online) 1st February Evening Shift

MCQ (Single Correct Answer)

-1

Match List - I with List - II.

List I (Number)	List II (Significant figure)
(A) 1001	(I) 3
(B) 010.1	(II) 4
(C) 100.100	(III) 5
(D) 0.0010010	(IV) 6

Choose the correct answer from the options given below :

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

JEE Main 2024 (Online) 1st February Morning Shift

MCQ (Single Correct Answer)

-1

10 divisions on the main scale of a Vernier calliper coincide with 11 divisions on the Vernier scale. If each division on the main scale is of 5 units, the least count of the instrument is :

$\frac{5}{11}$

$\frac{10}{11}$

$\frac{50}{11}$

$\frac{1}{2}$

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