JEE Main 2013 (Offline) | Units & Measurements Question 160 | Physics

Let [$${\varepsilon _0}$$] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:

$${\varepsilon _0} = \left[ {{M^{ - 1}}{L^{ - 3}}{T^2}A} \right]$$

$${\varepsilon _0} = $$$$\left[ {{M^{ - 1}}{L^{ - 3}}{T^4}{A^2}} \right]$$

$${\varepsilon _0} = \left[ {{M^1}{L^2}{T^1}{A^2}} \right]$$

$${\varepsilon _0} = \left[ {{M^1}{L^2}{T^1}A} \right]$$

AIEEE 2012

MCQ (Single Correct Answer)

-1

A spectrometer gives the following reading when used to measure the angle of a prism.
Main scale reading: 58.5 degree
Vernier scale reading : 09 divisions
Given that 1 division on main scale corresponds to 0.5 degree. Total divisions on the vernier scale is 30 and match with 29 divisions of the main scale. The angle of the prism from the above data

58.59 degree

58.77 degree

58.65 degree

59 degree

AIEEE 2012

MCQ (Single Correct Answer)

-1

Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are 3% each, then error in the value of resistance of the wire is

6 %

zero

1 %

3 %

AIEEE 2011

MCQ (Single Correct Answer)

-1

A screw gauge gives the following reading when used to measure the diameter of a wire.
Main scale reading : 0 mm
Circular scale reading : 52 divisions
Given that 1 mm on main scale corresponds to 100 divisions of the circular scale.
The diameter of wire from the above date is:

0.052 cm

0.026 cm

0.005 cm

0.52 cm

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