JEE Main 2022 (Online) 25th July Morning Shift | Units & Measurements Question 67 | Physics

If momentum [P], area $$[\mathrm{A}]$$ and time $$[\mathrm{T}]$$ are taken as fundamental quantities, then the dimensional formula for coefficient of viscosity is :

$$\left[\mathrm{P} \,\mathrm{A}^{-1} \mathrm{~T}^{0}\right]$$

$$\left[\mathrm{P} \,\mathrm{A}\mathrm{~T}^{-1}\right]$$

$$\left[\mathrm{P}\,\mathrm{A}^{-1} \mathrm{~T}\right]$$

$$\left[\mathrm{P} \,\mathrm{A}^{-1} \mathrm{~T}^{-1}\right]$$

JEE Main 2022 (Online) 30th June Morning Shift

MCQ (Single Correct Answer)

-1

If n main scale divisions coincide with (n + 1) vernier scale divisions. The least count of vernier callipers, when each centimetre on the main scale is divided into five equal parts, will be :

$${2 \over {n + 1}}$$ mm

$${5 \over {n + 1}}$$ mm

$${1 \over {2n}}$$ mm

$${1 \over {5n}}$$ mm

JEE Main 2022 (Online) 28th June Evening Shift

MCQ (Single Correct Answer)

-1

Velocity (v) and acceleration (a) in two systems of units 1 and 2 are related as $${v_2} = {n \over {{m^2}}}{v_1}$$ and $${a_2} = {{{a_1}} \over {mn}}$$ respectively. Here m and n are constants. The relations for distance and time in two systems respectively are :

$${{{n^3}} \over {{m^3}}}{L_1} = {L_2}$$ and $${{{n^2}} \over m}{T_1} = {T_2}$$

$${L_1} = {{{n^4}} \over {{m^2}}}{L_2}$$ and $${T_1} = {{{n^2}} \over m}{T_2}$$

$${L_1} = {{{n^2}} \over m}{L_2}$$ and $${T_1} = {{{n^4}} \over {{m^2}}}{T_2}$$

$${{{n^2}} \over m}{L_1} = {L_2}$$ and $${{{n^4}} \over {{m^2}}}{T_1} = {T_2}$$

JEE Main 2022 (Online) 27th June Evening Shift

MCQ (Single Correct Answer)

-1

The SI unit of a physical quantity is pascal-second. The dimensional formula of this quantity will be :

[ML^$$-$$1T^$$-$$1]

[ML^$$-$$1T^$$-$$2]

[ML²T^$$-$$1]

[M^$$-$$1L³T⁰]