JEE Main 2024 (Online) 1st February Morning Shift | Aldehydes, Ketones and Carboxylic Acids Question 19 | Chemistry

List I (Reactions)	List II (Reagents)
(A)	(I) CH₃MgBr, H₂O
(B) C₆H₅COC₆H₅ ⟶ C₆H₅CH=C₆H₅	(II) Zn(Hg) and conc. HCl
(C) C₆H₅CHO ⟶ C₆H₅CH(OH)CH₃	(III) NaBH₄, H⁺
(D)	(IV) DIBAL-H, H₂O

Choose the correct answer from the options given below :

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

(A)-(IV), (B)-(II), (C)-(III), (D)-(I)

(A)-(IV), (B)-(II), (C)-(I), (D)-(III)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

JEE Main 2024 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

Identify major product 'P' formed in the following reaction.

JEE Main 2024 (Online) 31st January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 26 English

JEE Main 2024 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

Identify the name reaction.

JEE Main 2024 (Online) 31st January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 25 English

Stephen Reaction

Etard Reaction

Gatterman - Koch Reaction

Rosenmund Reduction

JEE Main 2024 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

Salicylaldehyde is synthesized from phenol, when reacted with

$$\mathrm{HCCl}_3, \mathrm{NaOH}$$

$$\mathrm{CO}_2, \mathrm{NaOH}$$

JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 20 English Option 3

CCl$$_4$$, NaOH

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