1
JEE Main 2021 (Online) 20th July Morning Shift
Numerical
+4
-1
An average person needs about 10000 kJ energy per day. The amount of glucose (molar mass = 180.0 g mol$$-$$1) needed to meet this energy requirement is ____________ g.

(Use : $$\Delta$$CH(glucose) = $$-$$2700 kJ mol$$-$$1)
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2
JEE Main 2021 (Online) 18th March Evening Shift
Numerical
+4
-1
10.0 mL of Na2CO3 solution is titrated against 0.2 M HCl solution. The following titre values were obtained in 5 readings :

4.8 mL, 4.9 mL, 5.0 mL, 5.0 mL and 5.0 mL

Based on these readings, and convention of titrimetric estimation the concentration of Na2CO3 solution is ___________ mM.

(Round off to the Nearest Integer).
Your input ____
3
JEE Main 2021 (Online) 18th March Morning Shift
Numerical
+4
-1
__________ grams of 3-Hydroxy propanal (MW = 74) must be dehydrated to produce 7.8 g of acrolein (MW = 56) (C3H4O) if the percentage yield is 64. (Round off to the Nearest Integer).

[Given : Atomic masses : C : 12.0 u, H : 1.0 u, O : 16.0 u ]
Your input ____
4
JEE Main 2021 (Online) 18th March Morning Shift
Numerical
+4
-1
A reaction of 0.1 mole of Benzylamine with bromomethane gave 23 g of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are n $$\times$$ 10$$-$$1, when n = __________. (Round off to the Nearest Integer).

(Given : Atomic masses : C : 12.0 u, H : 1.0 u, N : 14.0 u, Br : 80.0 u]
Your input ____
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