33% OFF
ExamGOAL
MOST RELEVANT

JEE Main Ultimate Online Test Series - 2027

458 Tests
10,140 Questions
English & Hindi (हिन्दी) Languages
331 Topic Tests87 Chapter Tests30 Full Tests10 Part Tests
  • Most Relevant Questions for JEE Main 2027
  • JEE Main Predictive Percentile and Rank
  • Best Solution to Every Question
  • Very Detailed Analysis
₹999 ₹1,499
Save ₹500
Access valid till 31 May 2027
Check Out
1
JEE Main 2026 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Arrange the following isothermal processes in order of the magnitude of the work $(\mathrm{p}-\mathrm{V})$ involved between states 1 and 2.

A. Expansion in single stage $\mathrm{w}_{\mathrm{A}}$

B. Expansion in multi stages $w_B$

C. Compression in single stage $\mathrm{w}_{\mathrm{C}}$

D. Compression in multi stages $w_D$

Choose the correct option.

A

$$ \left|w_B\right|>\left|w_A\right|>\left|w_C\right|>\left|w_D\right| $$

B

$$ \left|w_C\right|>\left|w_D\right|>\left|w_A\right|>\left|w_B\right| $$

C

$$ \left|w_C\right|>\left|w_D\right|>\left|w_B\right|>\left|w_A\right| $$

D

$$ \left|w_B\right|>\left|w_A\right|>\left|w_D\right|>\left|w_C\right| $$

2
JEE Main 2026 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

When 0.25 moles of a non-volatile, non-ionizable solute was dissolved in 1 mole of a solvent the vapor pressure of solution was $x \%$ of vapor pressure of pure solvent. What is $x \%$ ?

A

50%

B

60%

C

70%

D

80%

3
JEE Main 2026 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

One mole each of He and $\mathrm{A}(\mathrm{g})$ are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium.

$$ \mathrm{A}(\mathrm{~g}) \rightleftharpoons \mathrm{B}(\mathrm{~g}) $$

$\mathrm{K}_{\mathrm{c}}$ for this reaction at 400 K is 4.0 . The partial pressures (in atm) of He and B(g) are respectively (at equilibrium)

(Assume $\mathrm{He}, \mathrm{A}(\mathrm{g})$ and $\mathrm{B}(\mathrm{g})$ behave as ideal gases)

(Given : $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )

A

3.28, 2.624

B

2.624, 3.28

C

3.28, 0.656

D

0.656, 6.56

4
JEE Main 2026 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

$$ \text { Consider the following data. } $$

$$ \begin{array}{|c|c|} \hline \text { Electrolyte } & \wedge^{\circ}_\mathbf{m}{\mathbf{(}} \mathbf{S ~ c m}^{\mathbf{2}} \mathbf{~ m o l}^{\mathbf{1}} \mathbf{)} \\ \hline \mathrm{BaCl}_2 & x_1 \\ \hline \mathrm{H}_2 \mathrm{SO}_4 & x_2 \\ \hline \mathrm{HCl} & x_3 \\ \hline \end{array} $$

$\mathrm{BaSO}_4$ is sparingly soluble in water. If the conductivity of the saturated $\mathrm{BaSO}_4$ solution is $x \mathrm{~S} \mathrm{~cm}^{-1}$ then the solubility product of $\mathrm{BaSO}_4$ can be given as (Here $\wedge_{\mathrm{m}}=\wedge^{\circ}_{\mathrm{m}}$ )

A

$\frac{10^6 x^2}{\alpha^2\left(x_1+x_2-2 x_3\right)^2}$

B

$$ \frac{x^2}{\left(x_1+x_2-2 x_3\right)^2} $$

C

$$ \frac{\alpha^2\left(x_1+x_2-2 x_3\right)^2}{10^6 x^2} $$

D

$$ \frac{x^2}{\left(x_1+x_2+2 x_3\right)^2} $$

JEE Main Papers

All year-wise previous year question papers

2023
2021