1
JEE Main 2026 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The area of the region bounded by the curves $x+3 y^2=0$ and $x+4 y^2=1$ is equal to :

A

$\frac{1}{3}$

B

$\frac{2}{3}$

C

$\frac{4}{3}$

D

$\frac{5}{3}$

2
JEE Main 2026 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let $y=y(x)$ be the solution of the differential equation :

$$ \frac{d y}{d x}+\left(\frac{6 x^2+\left(3 x^2+2 x^3+4\right) e^{-2 x}}{\left(x^3+2\right)\left(2+e^{-2 x}\right)}\right) y=2+e^{-2 x} $$

$x \in(-1,2)$, satisfying $y(0)=\frac{3}{2}$. If $y(1)=\alpha\left(2+e^{-2}\right)$, then $\alpha$ is equal to :

A

$\frac{13}{8}$

B

$\frac{6}{13}$

C

$\frac{12}{13}$

D

$\frac{13}{12}$

3
JEE Main 2026 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The integral $\int\limits_0^1 \cot ^{-1}\left(1+x+x^2\right) d x$ is equal to :

A

$$ 2 \tan ^{-1} 2+\frac{1}{2} \log _e\left(\frac{5}{4}\right)+\frac{\pi}{2} $$

B

$$ 2 \tan ^{-1} 2+\frac{1}{2} \log _e\left(\frac{5}{4}\right)-\frac{\pi}{2} $$

C

$$ 2 \tan ^{-1} 2-\frac{1}{2} \log _e\left(\frac{5}{4}\right)+\frac{\pi}{2} $$

D

$$ 2 \tan ^{-1} 2-\frac{1}{2} \log _e\left(\frac{5}{4}\right)-\frac{\pi}{2} $$

4
JEE Main 2026 (Online) 4th April Evening Shift
Numerical
+4
-1
Change Language

From a month of 31 days, 3 different dates are selected at random. If the probability that these dates are in an increasing A.P. is equal to $\frac{a}{b}$, where $a, b \in$ N and $\operatorname{gcd}(a, b)=1$, then $a+b$ is equal to $\_\_\_\_$

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