1
JEE Main 2026 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let $\hat{u}$ and $\hat{v}$ be unit vectors inclined at an acute angle such that $|\hat{u} \times \hat{v}|=\frac{\sqrt{3}}{2}$. If $\overrightarrow{\mathrm{A}}=\lambda \hat{u}+\hat{v}+(\hat{u} \times \hat{v})$, then $\lambda$ is equal to:

A

$$ \frac{4}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{u})-\frac{2}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{v}) $$

B

$$ \frac{2}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{u})-\frac{1}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{v}) $$

C

$$ \frac{4}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{u})+\frac{2}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{v}) $$

D

$$ (\overrightarrow{\mathrm{A}} \cdot \hat{u})-\frac{1}{2}(\overrightarrow{\mathrm{~A}} \cdot \hat{v}) $$

2
JEE Main 2026 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let for some $\alpha \in \mathbb{R}, f: \mathbb{R} \rightarrow \mathbb{R}$ be a function satisfying $f(x+y)=f(x)+2 y^2+y+\alpha x y$ for all $x, y \in \mathbb{R}$. If $f(0)=-1$ and $f(1)=2$, then the value of $\sum\limits_{n=1}^5(\alpha+f(n))$ is :

A

110

B

140

C

150

D

170

3
JEE Main 2026 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let

$\mathrm{A}=\{(a, b, c): a, b, c$ are non-negative integers and $a+b+2 c=22\}$.

Then $n(\mathrm{~A})$ is equal to :

A

121

B

124

C

144

D

169

4
JEE Main 2026 (Online) 4th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The area of the region bounded by the curves $x+3 y^2=0$ and $x+4 y^2=1$ is equal to :

A

$\frac{1}{3}$

B

$\frac{2}{3}$

C

$\frac{4}{3}$

D

$\frac{5}{3}$

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