$\frac{5 \mathrm{R}}{36}, \frac{3 \mathrm{R}}{16}, \frac{21 \mathrm{R}}{100}$

$\frac{7 \mathrm{R}}{144}, \frac{3 \mathrm{R}}{16}, \frac{16 \mathrm{R}}{255}$

$\frac{3 \mathrm{R}}{4}, \frac{3 \mathrm{R}}{16}, \frac{7 \mathrm{R}}{144}$

$\frac{5 \mathrm{R}}{36}, \frac{8 \mathrm{R}}{9}, \frac{15 \mathrm{R}}{16}$

Compound y will dissolve in $\mathrm{NaHCO}_3$ and evolve a gas.

Compound x is more acidic than compound y .

Both compounds x and y will dissolve in NaOH .

Both compounds x and y will burn with sooty flame.

$\mathrm{CH} \equiv \mathrm{C}^{-}>\mathrm{CH}_3-\mathrm{CH}_2^{-}>\mathrm{CH}_2=\mathrm{CH}^{-}$

$\mathrm{CH}_2=\mathrm{CH}^{-}>\mathrm{CH} \equiv \mathrm{C}^{-}>\mathrm{CH}_3-\mathrm{CH}_2^{-}$

$\mathrm{CH} \equiv \mathrm{C}^{-}>\mathrm{CH}_2=\mathrm{CH}^{-}>\mathrm{CH}_3-\mathrm{CH}_2^{-}$

$\mathrm{CH}_3-\mathrm{CH}_2^{-}>\mathrm{CH}_2=\mathrm{CH}^{-}>\mathrm{CH} \equiv \mathrm{C}^{-}$

D

B

C

A