Given below are two statements :

Statement I : Hybridisation, shape and spin only magnetic moment of $\mathrm{K}_3\left[\mathrm{Co}\left(\mathrm{CO}_3\right)_3\right]$ is $\mathrm{sp}^3 \mathrm{~d}^2$, octahedral and 4.9 BM respectively.

Statement II : Geometry, hybridisation and spin only magnetic moment values $(B M)$ of the ions $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-},\left[\mathrm{MnBr}_4\right]^{2-}$ and $\left[\mathrm{CoF}_6\right]^{3-}$ respectively are square planar, tetrahedral, octahedral; $\mathrm{dsp}^2, \mathrm{sp}^3, \mathrm{sp}^3 \mathrm{~d}^2$ and $0,5.9,4.9$.

In the light of the above statements, choose the correct answer from the options given below

A solution is prepared by dissolving 0.3 g of a non-volatile non-electrolyte solute 'A' of molar mass $60 \mathrm{~g} \mathrm{~mol}^{-1}$ and 0.9 g of a non-volatile non-electrolyte solute ' B ' of molar mass $180 \mathrm{~g} \mathrm{~mol}^{-1}$ in $100 \mathrm{~mL} \mathrm{H}_2 \mathrm{O}$ at $27^{\circ} \mathrm{C}$. Osmotic pressure of the solution will be

[Given: $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ ]

Given below are two statements:

Statement I : The number of paramagnetic species among $\left[\mathrm{CoF}_6\right]^{3-},\left[\mathrm{TiF}_6\right]^{3-}$, $\mathrm{V}_2 \mathrm{O}_5$ and $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$ is 3 .

Statement II :

$\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]<\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]<\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{SO}_4 \cdot \mathrm{H}_2 \mathrm{O}<\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3$ is the correct order in terms of number of unpaired electron(s) present in the complexes.

In the light of the above statements, choose the correct answer from the options given below

Given below are two statements :

Statement I : $\mathrm{K}>\mathrm{Mg}>\mathrm{Al}>\mathrm{B}$ is the correct order in terms of metallic character.

Statement II : Atomic radius is always greater than the ionic radius for any element.

In the light of the above statements, choose the correct answer from the options given below