Light wave travelling in air along x-direction is given by $${E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}$$. Then, the peak value of magnetic field of wave will be (Given c = 3 $$\times$$ 10⁸ ms^$$-$$1)

When you walk through a metal detector carrying a metal object in your pocket, it raises an alarm. This phenomenon works on :

An electron with energy 0.1 keV moves at right angle to the earth's magnetic field of 1 $$\times$$ 10^$$-$$4 Wbm^$$-$$2. The frequency of revolution of the electron will be :

(Take mass of electron = 9.0 $$\times$$ 10^$$-$$31 kg)

A current of 15 mA flows in the circuit as shown in figure. The value of potential difference between the points A and B will be: