1
JEE Main 2020 (Online) 5th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two capacitors of capacitances C and 2C are charged to potential differences V and 2V, respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is :
A
Zero
B
$${3 \over 2}C{V^2}$$
C
$${9 \over 2}C{V^2}$$
D
$${{25} \over 6}C{V^2}$$
2
JEE Main 2020 (Online) 5th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Three different processes that can occur in an ideal monoatomic gas are shown in the P vs V diagram. The paths are labelled as A $$ \to $$ B, A $$ \to $$ C and A $$ \to $$ D. The change in internal energies during these process are taken as EAB, EAC and EAD and the work done as WAB, WAC and WAD.
The correct relation between these parameters are : JEE Main 2020 (Online) 5th September Morning Slot Physics - Heat and Thermodynamics Question 215 English
A
EAB < EAC < EAD, WAB > 0, WAC > WAD
B
EAB = EAC = EAD, WAB > 0, WAC = 0, WAD < 0
C
EAB > EAC > EAD, WAB < WAC < WAD
D
EAB = EAC < EAD, WAB > 0, WAC = 0, WAD < 0
3
JEE Main 2020 (Online) 5th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A solid sphere of radius R carries a charge Q + q distributed uniformly over its volume. A very small point like piece of it of mass m gets detached from the bottom of the sphere and falls down vertically under gravity. This piece carries charge q. If it acquires a speed v when it has fallen through a vertical height y (see figure), then :
(assume the remaining portion to be spherical). JEE Main 2020 (Online) 5th September Morning Slot Physics - Electrostatics Question 116 English
A
v2 = $$y\left[ {{{qQ} \over {4\pi {\varepsilon _0}R\left( {R + y} \right)m}} + g} \right]$$
B
v2 = $$2y\left[ {{{qQR} \over {4\pi {\varepsilon _0}{{\left( {R + y} \right)}^3}m}} + g} \right]$$
C
v2 = $$2y\left[ {{{qQ} \over {4\pi {\varepsilon _0}R\left( {R + y} \right)m}} + g} \right]$$
D
v2 = $$y\left[ {{{qQ} \over {4\pi {\varepsilon _0}{R^2}ym}} + g} \right]$$
4
JEE Main 2020 (Online) 5th September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The value of the acceleration due to gravity is g1 at a height h = $${R \over 2}$$ (R = radius of the earth) from the surface of the earth. It is again equal to g1 at a depth d below the surface of the earth. The ratio $$\left( {{d \over R}} \right)$$ equals :
A
$${5 \over 9}$$
B
$${1 \over 9}$$
C
$${7 \over 9}$$
D
$${4 \over 9}$$
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