1
JEE Main 2020 (Online) 3rd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the frequency distribution :
Variate (x) :      x1   x2   x3 ....  x15
Frequency (f) : f1    f2   f3 ...... f15
where 0 < x1 < x2 < x3 < ... < x15 = 10 and
$$\sum\limits_{i = 1}^{15} {{f_i}} $$ > 0, the standard deviation cannot be :
A
6
B
1
C
4
D
2
2
JEE Main 2020 (Online) 3rd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If y2 + loge (cos2x) = y,
$$x \in \left( { - {\pi \over 2},{\pi \over 2}} \right)$$, then :
A
|y''(0)| = 2
B
|y'(0)| + |y''(0)| = 3
C
y''(0) = 0
D
|y'(0)| + |y"(0)| = 1
3
JEE Main 2020 (Online) 3rd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The function, f(x) = (3x – 7)x2/3, x $$ \in $$ R, is increasing for all x lying in :
A
$$\left( { - \infty ,0} \right) \cup \left( {{3 \over 7},\infty } \right)$$
B
$$\left( { - \infty ,0} \right) \cup \left( {{{14} \over {15}},\infty } \right)$$
C
$$\left( { - \infty ,{{14} \over {15}}} \right)$$
D
$$\left( { - \infty ,{{14} \over {15}}} \right) \cup \left( {0,\infty } \right)$$
4
JEE Main 2020 (Online) 3rd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The value of (2.1P0 – 3.2P1 + 4.3P2 .... up to 51th term)
+ (1! – 2! + 3! – ..... up to 51th term) is equal to :
A
1
B
1 + (51)!
C
1 – 51(51)!
D
1 + (52)!
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