1
JEE Main 2020 (Online) 2nd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A capillary tube made of glass of radius 0.15 mm is dipped vertically in a beaker filled with methylene iodide (surface tension = 0.05 Nm–1, density = 667 kg m–3) which rises to height h in the tube. It is observed that the two tangents drawn from liquid-glass interfaces (from opp. sides of the capillary) make an angle of 60o with one another. Then h is close to (g = 10 ms–2)
A
0.049 m
B
0.087 m
C
0.137 m
D
0.172 m
2
JEE Main 2020 (Online) 2nd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The figure shows a region of length ‘l’ with a uniform magnetic field of 0.3 T in it and a proton entering the region with velocity 4 $$ \times $$ 105 ms–1 making an angle 60o with the field. If the proton completes 10 revolution by the time it cross the region shown, ‘l’ is close to
(mass of proton = 1.67 $$ \times $$ 10–27 kg, charge of the proton = 1.6 $$ \times $$ 10–19 C) JEE Main 2020 (Online) 2nd September Evening Slot Physics - Magnetic Effect of Current Question 145 English
A
0.22 m
B
0.11 m
C
0.88 m
D
0.44 m
3
JEE Main 2020 (Online) 2nd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The displacement time graph of a particle executing S.H.M is given in figure :
(sketch is schematic and not to scale) JEE Main 2020 (Online) 2nd September Evening Slot Physics - Simple Harmonic Motion Question 107 English
Which of the following statements is/are true for this motion?
(A) The force is zero at t = $${{3T} \over 4}$$
(B) The acceleration is maximum at t = T
(C) The speed is maximum at t = $${{T} \over 4}$$
(D) The P.E. is equal to K.E. of the oscillation at t = $${{T} \over 2}$$
A
(B), (C) and (D)
B
(A), (B) and (C)
C
(A) and (D)
D
(A), (B) and (D)
4
JEE Main 2020 (Online) 2nd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If momentum (P), area (A) and time (T) are taken to be the fundamental quantities then the dimensional formula for energy is
A
[P2AT–2]
B
$$\left[ {{P^{{1 \over 2}}}A{T^{ - 1}}} \right]$$
C
$$\left[ {P{A^{{1 \over 2}}}{T^{ - 1}}} \right]$$
D
[PA–1T–2]
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