1
JEE Main 2019 (Online) 12th January Evening Slot
+4
-1
A galvanometer, whose resistance is 50 ohm, has 25 divisions in it. When a current of 4 $$\times$$ 10–4 A passes through it, its needle ( pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5 V, it should be connected to a resistance of :
A
200 ohm
B
250 ohm
C
6200 ohm
D
6250 ohm
2
JEE Main 2019 (Online) 12th January Evening Slot
+4
-1
In the given circuit diagram, the currents, I1 = – 0.3 A, I4 = 0.8 A and I5 = 0.4 A, are flowing as shown. The currents I2, I3 and I6, respectively, are :

A
1.1 A, – 0.4 A, 0.4 A
B
$$-$$ 0.4 A, 0.4 A, 1.1 A
C
0.4 A, 1.1 A, 0.4 A
D
1.1 A, 0.4 A, 0.4 A
3
JEE Main 2019 (Online) 12th January Morning Slot
+4
-1
The galvanometer deflection, when key K1 is closed but K2 is open, equals $$\theta$$0 (see figure). On closing K2 also and adjusting R2 to 5$$\Omega$$, the deflection in galvanometer becomes $${{{\theta _0}} \over 5}.$$ . The resistance of the galvanometer is, then, given by [Neglect the internal resistance of battery] :

A
5 $$\Omega$$
B
25 $$\Omega$$
C
12 $$\Omega$$
D
22 $$\Omega$$
4
JEE Main 2019 (Online) 12th January Morning Slot
+4
-1
In the figure shown, a circuit contains two identical resistors with resistance R = 5$$\Omega$$ and an inductance with L = 2mH. An ideal battery of 15 V is connected in the circuit. What will be the current through the battery long after the switch is closed ?

A
6 A
B
7.5 A
C
3 A
D
5.5 A
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