JEE Main 2023 (Online) 31st January Evening Shift | Current Electricity Question 125 | Physics

The $\mathrm{H}$ amount of thermal energy is developed by a resistor in $10 \mathrm{~s}$ when a current of $4 \mathrm{~A}$ is passed through it. If the current is increased to $16 \mathrm{~A}$, the thermal energy developed by the resistor in $10 \mathrm{~s}$ will be :

$\frac{\mathrm{H}}{4}$

$16 \mathrm{H}$

$4 \mathrm{H}$

JEE Main 2023 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

-1

The drift velocity of electrons for a conductor connected in an electrical circuit is $$\mathrm{V}_{\mathrm{d}}$$. The conductor in now replaced by another conductor with same material and same length but double the area of cross section. The applied voltage remains same. The new drift velocity of electrons will be

$$\frac{V_{d}}{4}$$

$$\mathrm{V}_{\mathrm{d}}$$

$$2 \mathrm{~V}_{\mathrm{d}}$$

$$\frac{V_{d}}{2}$$

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

The equivalent resistance between $A$ and $B$ is _________.

JEE Main 2023 (Online) 30th January Evening Shift Physics - Current Electricity Question 135 English

$\frac{1}{2} \Omega$

$\frac{2}{3} \Omega$

$\frac{3}{2} \Omega$

$\frac{1}{3} \Omega$

JEE Main 2023 (Online) 30th January Morning Shift

MCQ (Single Correct Answer)

-1

The charge flowing in a conductor changes with time as $$\mathrm{Q}(\mathrm{t})=\alpha \mathrm{t}-\beta \mathrm{t}^{2}+\gamma \mathrm{t}^{3}$$. Where $$\alpha, \beta$$ and $$\gamma$$ are constants. Minimum value of current is :

$$\beta-\frac{\alpha^{2}}{3 \gamma}$$

$$\alpha-\frac{3 \beta^{2}}{\gamma}$$

$$\alpha-\frac{\beta^{2}}{3 \gamma}$$

$$\alpha-\frac{\gamma^{2}}{3 \beta}$$

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