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1
JEE Main 2017 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
The major product of the following reaction is :

JEE Main 2017 (Online) 9th April Morning Slot Chemistry - Hydrocarbons Question 110 English
A
JEE Main 2017 (Online) 9th April Morning Slot Chemistry - Hydrocarbons Question 110 English Option 1
B
JEE Main 2017 (Online) 9th April Morning Slot Chemistry - Hydrocarbons Question 110 English Option 2
C
JEE Main 2017 (Online) 9th April Morning Slot Chemistry - Hydrocarbons Question 110 English Option 3
D
JEE Main 2017 (Online) 9th April Morning Slot Chemistry - Hydrocarbons Question 110 English Option 4
2
JEE Main 2016 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires 375 mL air containing 20% O2 by volume for complete combustion. After combustion the gases occupy 345 mL. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is:
A
C3H8
B
C4H8
C
C4H10
D
C3H6
3
JEE Main 2016 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
The reaction of propene with HOCl (Cl2 + H2O) proceeds through the intermediate:
A
$$\mathrm{CH}_{3}-\mathrm{CH}^{+}-\mathrm{CH}_{2}-\mathrm{OH}$$
B
$$\mathrm{CH}_{3}-\mathrm{CHCl}-\mathrm{CH}_{2}^{+}$$
C
CH3 - CH+ - CH2 - OH
D
$$\mathrm{CH}_{3}-\mathrm{CH}^{+}-\mathrm{CH}_{2}-\mathrm{Cl}$$
4
JEE Main 2015 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
Which compound would give $$5$$ - keto - $$2$$ - methylhexanal upon ozonolysis?
A
JEE Main 2015 (Offline) Chemistry - Hydrocarbons Question 114 English Option 1
B
JEE Main 2015 (Offline) Chemistry - Hydrocarbons Question 114 English Option 2
C
JEE Main 2015 (Offline) Chemistry - Hydrocarbons Question 114 English Option 3
D
JEE Main 2015 (Offline) Chemistry - Hydrocarbons Question 114 English Option 4
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