JEE Main 2024 (Online) 30th January Evening Shift | Hydrocarbons Question 13 | Chemistry

$$\mathrm{A}=\mathrm{CH}_3-\mathrm{C} \equiv \stackrel{-}{\mathrm{C}} \mathrm{Na}^{+}, \mathrm{B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}$$

$$\mathrm{A}=\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2, \mathrm{~B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}$$

$$\mathrm{A}=\mathrm{CH}_3-\mathrm{C} \equiv \stackrel{-}{\mathrm{C}} \mathrm{Na}^{+}, \mathrm{B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3$$

$$\mathrm{A}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3, \mathrm{~B}=\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$$

JEE Main 2024 (Online) 30th January Morning Shift

MCQ (Single Correct Answer)

-1

In the given reactions, identify the reagent A and reagent B.

JEE Main 2024 (Online) 30th January Morning Shift Chemistry - Hydrocarbons Question 10 English

$$\mathrm{A}-\mathrm{CrO}_3 \quad \mathrm{~B}-\mathrm{CrO}_3$$

$$\mathrm{A}-\mathrm{CrO}_3 \quad \mathrm{~B}-\mathrm{CrO}_2 \mathrm{Cl}_2$$

A- $$\mathrm{CrO}_2 \mathrm{Cl}_2 \quad \mathrm{~B}-\mathrm{CrO}_3$$

$$\mathrm{A}-\mathrm{CrO}_2 \mathrm{Cl}_2 \quad \mathrm{~B}-\mathrm{CrO}_2 \mathrm{Cl}_2$$

JEE Main 2024 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

-1

Identify product A and product B :

JEE Main 2024 (Online) 29th January Morning Shift Chemistry - Hydrocarbons Question 15 English

JEE Main 2024 (Online) 29th January Morning Shift Chemistry - Hydrocarbons Question 15 English Option 3

JEE Main 2024 (Online) 29th January Morning Shift Chemistry - Hydrocarbons Question 15 English Option 4

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