1
JEE Main 2023 (Online) 1st February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

'$$\mathrm{X}$$' is :

JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Hydrocarbons Question 42 English

A
JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Hydrocarbons Question 42 English Option 1
B
JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Hydrocarbons Question 42 English Option 2
C
JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Hydrocarbons Question 42 English Option 3
D
JEE Main 2023 (Online) 1st February Evening Shift Chemistry - Hydrocarbons Question 42 English Option 4
2
JEE Main 2023 (Online) 1st February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

But-2-yne is reacted separately with one mole of Hydrogen as shown below :

JEE Main 2023 (Online) 1st February Morning Shift Chemistry - Hydrocarbons Question 40 English

A. A is more soluble than B.

B. The boiling point & melting point of A are higher and lower than B respectively.

C. A is more polar than B because dipole moment of A is zero.

D. $$\mathrm{Br_2}$$ adds easily to B than A.

Identify the incorrect statements from the options given below :

A
A and B only
B
A, C & D only
C
B, C & D only
D
C and D only
3
JEE Main 2023 (Online) 31st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
A hydrocarbon ' $\mathrm{X}$ ' with formula $\mathrm{C}_{6} \mathrm{H}_{8}$ uses two moles of $\mathrm{H}_{2}$ on catalytic hydrogenation of its one mole. On ozonolysis, ' $\mathrm{X}$ ' yields two moles of methane dicarbaldehyde. The hydrocarbon ' $\mathrm{X}$ ' is:
A
hexa-1, 3, 5-triene
B
cyclohexa-1, 4-diene
C
cyclohexa - 1,3 - diene
D
1-methylcyclopenta-1, 4-diene
4
JEE Main 2023 (Online) 31st January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Choose the correct set of reagents for the following conversion.

trans $$\left(\mathrm{Ph}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\right) \rightarrow \operatorname{cis}\left(\mathrm{Ph}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\right)$$

A
$$\mathrm{Br_2,alc\cdot KOH,NaNH_2,H_2}$$ Lindlar Catalyst
B
$$\mathrm{Br_2,aq\cdot KOH,NaNH_2,Na}$$ (Liq NH$$_3$$)
C
$$\mathrm{Br_2,alc\cdot KOH,NaNH_2,Na}$$ (Liq NH$$_3$$)
D
$$\mathrm{Br_2,aq\cdot KOH,NaNH_2,H_2}$$ Lindlar Catalyst
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