JEE Main 2023 (Online) 29th January Morning Shift | Biomolecules Question 82 | Chemistry

JEE Main 2023 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

-1

Number of cyclic tripeptides formed with 2 amino acids A and B is :

JEE Main 2023 (Online) 25th January Morning Shift

MCQ (Single Correct Answer)

-1

Match items of Row I with those of Row II.

Row I :

JEE Main 2023 (Online) 25th January Morning Shift Chemistry - Biomolecules Question 75 English

Row II :

(i) $$\alpha$$-$$\mathrm{D}$$-$$(-)$$-$$\mathrm{Fructofuranose}$$

(ii) $$\beta$$-D-$$(-)$$-Fructofuranose

(iii) $$\alpha$$-D-$$(-)$$ Glucopyranose

(iv) $$\beta$$-D-$$(-)$$-Glucopyranose

Correct match is

A $$\to$$ iii, B $$\to$$ iv, C $$\to$$ i, D $$\to$$ ii

A $$\to$$ iv, B $$\to$$ iii, C $$\to$$ i, D $$\to$$ ii

A $$\to$$ i, B $$\to$$ ii, C $$\to$$ iii, D $$\to$$ iv

A $$\to$$ iii, B $$\to$$ iv, C $$\to$$ ii, D $$\to$$ i

JEE Main 2022 (Online) 29th July Evening Shift

MCQ (Single Correct Answer)

-1

Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Amylose is insoluble in water.

Reason R: Amylose is a long linear molecule with more than 200 glucose units.

In the light of the above statements, choose the correct answer from the options given below.

Both $$\mathbf{A}$$ and $$\mathbf{R}$$ are correct and $$\mathbf{R}$$ is the correct explanation of $$\mathbf{A}$$.

Both $$\mathbf{A}$$ and $$\mathbf{R}$$ are correct but $$\mathbf{R}$$ is NOT the correct explanation of $$\mathbf{A}$$.

$$\mathbf{A}$$ is correct but $$\mathbf{R}$$ is not correct

$$\mathbf{A}$$ is not correct but $$\mathbf{R}$$ is correct.

JEE Main 2022 (Online) 28th July Evening Shift

MCQ (Single Correct Answer)

-1

The formulas of A and B for the following reaction sequence

JEE Main 2022 (Online) 28th July Evening Shift Chemistry - Biomolecules Question 89 English

are

$$\mathrm{A}=\mathrm{C}_{7} \mathrm{H}_{14} \mathrm{O}_{8}, \quad \mathrm{~B}=\mathrm{C}_{6} \mathrm{H}_{14}$$

$$\mathrm{A}=\mathrm{C}_{7} \mathrm{H}_{13} \mathrm{O}_{7}, \quad \mathrm{~B}=\mathrm{C}_{7} \mathrm{H}_{14} \mathrm{O}$$

$$\mathrm{A}=\mathrm{C}_{7} \mathrm{H}_{12} \mathrm{O}_{8}, \quad \mathrm{~B}=\mathrm{C}_{6} \mathrm{H}_{14}$$

$$\mathrm{A}=\mathrm{C}_{7} \mathrm{H}_{14} \mathrm{O}_{8}, \quad \mathrm{~B}=\mathrm{C}_{6} \mathrm{H}_{14} \mathrm{O}_{6}$$

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