1
JEE Main 2022 (Online) 29th July Evening Shift
+4
-1

Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Amylose is insoluble in water.

Reason R: Amylose is a long linear molecule with more than 200 glucose units.

In the light of the above statements, choose the correct answer from the options given below.

A
Both $$\mathbf{A}$$ and $$\mathbf{R}$$ are correct and $$\mathbf{R}$$ is the correct explanation of $$\mathbf{A}$$.
B
Both $$\mathbf{A}$$ and $$\mathbf{R}$$ are correct but $$\mathbf{R}$$ is NOT the correct explanation of $$\mathbf{A}$$.
C
$$\mathbf{A}$$ is correct but $$\mathbf{R}$$ is not correct
D
$$\mathbf{A}$$ is not correct but $$\mathbf{R}$$ is correct.
2
JEE Main 2022 (Online) 28th July Evening Shift
+4
-1

The formulas of A and B for the following reaction sequence

are

A
$$\mathrm{A}=\mathrm{C}_{7} \mathrm{H}_{14} \mathrm{O}_{8}, \quad \mathrm{~B}=\mathrm{C}_{6} \mathrm{H}_{14}$$
B
$$\mathrm{A}=\mathrm{C}_{7} \mathrm{H}_{13} \mathrm{O}_{7}, \quad \mathrm{~B}=\mathrm{C}_{7} \mathrm{H}_{14} \mathrm{O}$$
C
$$\mathrm{A}=\mathrm{C}_{7} \mathrm{H}_{12} \mathrm{O}_{8}, \quad \mathrm{~B}=\mathrm{C}_{6} \mathrm{H}_{14}$$
D
$$\mathrm{A}=\mathrm{C}_{7} \mathrm{H}_{14} \mathrm{O}_{8}, \quad \mathrm{~B}=\mathrm{C}_{6} \mathrm{H}_{14} \mathrm{O}_{6}$$
3
JEE Main 2022 (Online) 28th July Morning Shift
+4
-1

For the below given cyclic hemiacetal (X), the correct pyranose structure is :

A
B
C
D
4
JEE Main 2022 (Online) 27th July Evening Shift
+4
-1

Match List - I with Match List - II.

List - I List - II
(A) Glucose + HI (I) Gluconic acid
(B) Glucose + Br$$_2$$ water (II) Glucose pentacetate
(C) Glucose + acetic anhydride (III) Saccharic acid
(D) Glucose + HNO$$_3$$ (IV) Hexane

Choose the correct answer from the options given below:

A
(A) - (IV), (B) - (I), (C) -(II), (D) - (III)
B
(A) - (IV), (B) - (III), (C) -(II), (D) - (I)
C
(A) - (III), (B) - (I), (C) -(IV), (D) - (II)
D
(A) - (I), (B) - (III), (C) -(IV), (D) - (II)
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