1
JEE Main 2022 (Online) 25th July Morning Shift
+4
-1

$$\mathrm{SO}_{2} \mathrm{Cl}_{2}$$ on reaction with excess of water results into acidic mixture

$$\mathrm{SO}_{2} \mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}+2 \mathrm{HCl}$$

16 moles of $$\mathrm{NaOH}$$ is required for the complete neutralisation of the resultant acidic mixture. The number of moles of $$\mathrm{SO}_{2} \mathrm{Cl}_{2}$$ used is :

A
16
B
8
C
4
D
2
2
JEE Main 2022 (Online) 29th June Evening Shift
+4
-1
Out of Syllabus

Using the rules for significant figures, the correct answer for the expression $${{0.02858 \times 0.112} \over {0.5702}}$$ will be

A
0.005613
B
0.00561
C
0.0056
D
0.006
3
JEE Main 2022 (Online) 29th June Morning Shift
+4
-1

Production of iron in blast furnace follows the following equation

Fe3O4(s) + 4CO(g) $$\to$$ 3Fe(l) + 4CO2(g)

when 4.640 kg of Fe3O4 and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is :

[Given : Molar Atomic mass (g mol$$-$$1) : Fe = 56, Molar Atomic mass (g mol$$-$$1) : O = 16, Molar Atomic mass (g mol$$-$$1) : C = 12]

A
1400
B
2200
C
3360
D
4200
4
JEE Main 2022 (Online) 28th June Evening Shift
+4
-1

Compound A contains 8.7% Hydrogen, 74% Carbon and 17.3% Nitrogen. The molecular formula of the compound is,

Given : Atomic masses of C, H and N are 12, 1 and 14 amu respectively.

The molar mass of the compound A is 162 g mol$$-$$1.

A
C4H6N2
B
C2H3N
C
C5H7N
D
C10H14N2
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