JEE Main 2019 (Online) 9th January Morning Slot | Some Basic Concepts of Chemistry Question 216 | Chemistry

An unknown chlorohydrocarbon has 3.55% of chlorine. If each molecule of the hydrocarbon has one chlorine atom only; chlorine atoms present in 1 g of chlorohydrocarbon are :
(Atomic wt. of Cl = 35.5 u; Avogadro constant = 6.023 $$ \times $$ 10²³ mol^-1)

6.023 $$ \times $$ 10²⁰

6.023 $$ \times $$ 10⁹

6.023 $$ \times $$ 10²¹

6.023 $$ \times $$ 10²³

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MCQ (Single Correct Answer)

-1

The ratio of mass percent of C and H of an organic compound (C_XH_YO_Z) is 6 : 1. If one molecule of the above compound (C_XH_YO_Z) contains half as much oxygen as required to burn one molecule of compound C_XH_Y completely to CO₂ and H₂O. The empirical formula of compound C_XH_YO_Z is

C₂H₄O₃

C₃H₆O₃

C₂H₄O

C₃H₄O₂

JEE Main 2018 (Online) 15th April Evening Slot

MCQ (Single Correct Answer)

-1

For per gram of reactant, the maximum quantity of N₂ gas is produced in which of the following thermal decomposition reactions ?
(Given : Atomic wt. - Cr = 52 u, Ba = 137 u)

(NH₄)₂Cr₂O₇(s) $$ \to $$ N₂(g) + 4H₂O(g) + Cr₂O₃(s)

2NH₄NO₃(s) $$ \to $$ 2 N₂(g) + 4H₂O(g) + O₂(g)

Ba(N₃)₂(s) $$ \to $$ Ba(s) + 3N₂(g)

2NH₃(g) $$ \to $$ N₂(g) + 3H₂(g)

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