1
JEE Main 2024 (Online) 31st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A sample of $$\mathrm{CaCO}_3$$ and $$\mathrm{MgCO}_3$$ weighed $$2.21 \mathrm{~g}$$ is ignited to constant weight of $$1.152 \mathrm{~g}$$. The composition of mixture is :

(Given molar mass in $$\mathrm{g} \mathrm{~mol}^{-1} \mathrm{CaCO}_3: 100, \mathrm{MgCO}_3: 84$$)

A
$$1.187 \mathrm{~g} \mathrm{~CaCO}_3+1.187 \mathrm{~g} \mathrm{~MgCO}_3$$
B
$$1.187 \mathrm{~g} \mathrm{~CaCO}_3+1.023 \mathrm{~g} \mathrm{~MgCO}_3$$
C
$$1.023 \mathrm{~g} \mathrm{~CaCO}_3+1.187 \mathrm{~g} \mathrm{~MgCO}_3$$
D
$$1.023 \mathrm{~g} \mathrm{~CaCO}_3+1.023 \mathrm{~g} \mathrm{~MgCO}_3$$
2
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

If a substance '$$A$$' dissolves in solution of a mixture of '$$B$$' and '$$C$$' with their respective number of moles as $$\mathrm{n}_{\mathrm{A}}, \mathrm{n}_{\mathrm{B}}$$ and $$\mathrm{n}_{\mathrm{C}_3}$$. Mole fraction of $$\mathrm{C}$$ in the solution is

A
$$\frac{n_C}{n_A \times n_B \times n_C}$$
B
$$\frac{n_B}{n_A+n_B}$$
C
$$\frac{n_C}{n_A+n_B+n_C}$$
D
$$\frac{n_C}{n_A-n_B-n_C}$$
3
JEE Main 2024 (Online) 27th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The quantity which changes with temperature is :

A
Molality
B
Molarity
C
Mole fraction
D
Mass percentage
4
JEE Main 2023 (Online) 12th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

A metal chloride contains $$55.0 \%$$ of chlorine by weight . $$100 \mathrm{~mL}$$ vapours of the metal chloride at STP weigh $$0.57 \mathrm{~g}$$. The molecular formula of the metal chloride is

(Given: Atomic mass of chlorine is $$35.5 \mathrm{u}$$)

A
$$\mathrm{MCl}_{2}$$
B
$$\mathrm{MCl}_{4}$$
C
$$\mathrm{MCl}_{3}$$
D
$$\mathrm{MCl}$$
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