Consider the following pairs of electrons

(A) (a) n = 3, $$l$$ = 1, m₁ = 1, m_s = + $${1 \over 2}$$

      (b) n = 3, 1 = 2, m₁ = 1, m_s = + $${1 \over 2}$$

(B) (a) n = 3, $$l$$ = 2, m₁ = $$-$$2, m_s = $$-$$$${1 \over 2}$$

      (b) n = 3, $$l$$ = 2, m₁ = $$-$$1, m_s = $$-$$$${1 \over 2}$$

(C) (a) n = 4, $$l$$ = 2, m₁ = 2, m_s = + $${1 \over 2}$$

      (b) n = 3, $$l$$ = 2, m₁ = 2, m_s = + $${1 \over 2}$$

The pairs of electrons present in degenerate orbitals is/are :

Given below are two statements.

Statement I : According to Bohr's model of an atom, qualitatively the magnitude of velocity of electron increases with decrease in positive charges on the nucleus as there is no strong hold on the electron by the nucleus.

Statement II : According to Bohr's model of an atom, qualitatively the magnitude of velocity of electron increases with decrease in principal quantum number.

In the light of the above statements, choose the most appropriate answer from the options given below :

If the Thompson model of the atom was correct, then the result of Rutherford's gold foil experiment would have been :

Given below are two statements :

Statement I : Rutherford's gold foil experiment cannot explain the line spectrum of hydrogen atom.

Statement II : Bohr's model of hydrogen atom contradicts Heisenberg' uncertainty principle.

In the light of the above statements, choose the most appropriate answer from the options given below :