JEE Main 2023 (Online) 31st January Evening Shift | Structure of Atom Question 61 | Chemistry

Arrange the following orbitals in decreasing order of energy.

A. $\mathrm{n}=3, \mathrm{l}=0, \mathrm{~m}=0$

B. $\mathrm{n}=4, \mathrm{l}=0, \mathrm{~m}=0$

C. $\mathrm{n}=3, \mathrm{l}=1, \mathrm{~m}=0$

D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}=1$

The correct option for the order is :

$\mathrm{B}>\mathrm{D}>\mathrm{C}>\mathrm{A}$

$\mathrm{A}>\mathrm{C}>\mathrm{B}>\mathrm{D}$

$\mathrm{D}>\mathrm{B}>\mathrm{A}>\mathrm{C}$

$\mathrm{D}>\mathrm{B}>\mathrm{C}>\mathrm{A}$

JEE Main 2023 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

-1

Which transition in the hydrogen spectrum would have the same wavelength as the Balmer type transition from $$\mathrm{n=4}$$ to $$\mathrm{n}=2$$ of $$\mathrm{He}^{+}$$ spectrum

$$\mathrm{n}=3$$ to $$\mathrm{n}=4$$

$$\mathrm{n}=2$$ to $$\mathrm{n}=1$$

$$\mathrm{n}=1$$ to $$\mathrm{n}=2$$

$$\mathrm{n}=1$$ to $$\mathrm{n}=3$$

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

Maximum number of electrons that can be accommodated in shell with $n=4$ are:

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

The wave function $(\Psi)$ of $2 \mathrm{~s}$ is given by

$$ \Psi_{2 \mathrm{~s}}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{r}{a_0}\right) e^{-r / 2 a_0} $$

At $r=r_0$, radial node is formed. Thus, $r_0$ in terms of $a_0$

$r_0=a_0$

$r_0=4 a_0$

$r_0=2 a_0$

$r_0=\frac{a_0}{2}$

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