JEE Main 2023 (Online) 31st January Evening Shift | Structure of Atom Question 17 | Chemistry

JEE Main 2023 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

Arrange the following orbitals in decreasing order of energy.

A. $\mathrm{n}=3, \mathrm{l}=0, \mathrm{~m}=0$

B. $\mathrm{n}=4, \mathrm{l}=0, \mathrm{~m}=0$

C. $\mathrm{n}=3, \mathrm{l}=1, \mathrm{~m}=0$

D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}=1$

The correct option for the order is :

$\mathrm{B}>\mathrm{D}>\mathrm{C}>\mathrm{A}$

$\mathrm{A}>\mathrm{C}>\mathrm{B}>\mathrm{D}$

$\mathrm{D}>\mathrm{B}>\mathrm{A}>\mathrm{C}$

$\mathrm{D}>\mathrm{B}>\mathrm{C}>\mathrm{A}$

JEE Main 2023 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

-1

$$\mathrm{Nd^{2+}}$$ = __________

$$\mathrm{4f^4 6s^2}$$

$$\mathrm{4f^3}$$

$$\mathrm{4f^4}$$

$$\mathrm{4f^2 6s^2}$$

JEE Main 2023 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

-1

Which transition in the hydrogen spectrum would have the same wavelength as the Balmer type transition from $$\mathrm{n=4}$$ to $$\mathrm{n}=2$$ of $$\mathrm{He}^{+}$$ spectrum

$$\mathrm{n}=3$$ to $$\mathrm{n}=4$$

$$\mathrm{n}=2$$ to $$\mathrm{n}=1$$

$$\mathrm{n}=1$$ to $$\mathrm{n}=2$$

$$\mathrm{n}=1$$ to $$\mathrm{n}=3$$

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

Maximum number of electrons that can be accommodated in shell with $n=4$ are: