1
JEE Main 2024 (Online) 5th April Evening Shift
+4
-1

A galvanometer of resistance $$100 \Omega$$ when connected in series with $$400 \Omega$$ measures a voltage of upto $$10 \mathrm{~V}$$. The value of resistance required to convert the galvanometer into ammeter to read upto $$10 \mathrm{~A}$$ is $$x \times 10^{-2} \Omega$$. The value of $$x$$ is :

A
2
B
20
C
800
D
200
2
JEE Main 2024 (Online) 5th April Morning Shift
+4
-1

In the given figure $$\mathrm{R}_1=10 \Omega, \mathrm{R}_2=8 \Omega, \mathrm{R}_3=4 \Omega$$ and $$\mathrm{R}_4=8 \Omega$$. Battery is ideal with emf $$12 \mathrm{~V}$$. Equivalent resistant of the circuit and current supplied by battery are respectively :

A
$$12 \Omega$$ and $$11.4 \mathrm{~A}$$
B
$$10.5 \Omega$$ and $$1.14 \mathrm{~A}$$
C
$$10.5 \Omega$$ and $$1 \mathrm{~A}$$
D
$$12 \Omega$$ and $$1 \mathrm{~A}$$
3
JEE Main 2024 (Online) 4th April Evening Shift
+4
-1

An electric bulb rated $$50 \mathrm{~W}-200 \mathrm{~V}$$ is connected across a $$100 \mathrm{~V}$$ supply. The power dissipation of the bulb is:

A
100 W
B
50 W
C
12.5 W
D
25 W
4
JEE Main 2024 (Online) 4th April Morning Shift
+4
-1

The value of net resistance of the network as shown in the given figure is :

A
$$(30 / 11) \Omega$$
B
$$6 \Omega$$
C
$$(5 / 2) \Omega$$
D
$$(15 / 4) \Omega$$
EXAM MAP
Medical
NEET