1
JEE Main 2024 (Online) 1st February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
JEE Main 2024 (Online) 1st February Evening Shift Chemistry - Hydrocarbons Question 19 English

Acid D formed in above reaction is :
A
Malonic acid
B
Oxalic acid
C
Succinic acid
D
Gluconic acid
2
JEE Main 2024 (Online) 31st January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Major product of the following reaction is -

JEE Main 2024 (Online) 31st January Evening Shift Chemistry - Hydrocarbons Question 17 English

A
JEE Main 2024 (Online) 31st January Evening Shift Chemistry - Hydrocarbons Question 17 English Option 1
B
JEE Main 2024 (Online) 31st January Evening Shift Chemistry - Hydrocarbons Question 17 English Option 2
C
JEE Main 2024 (Online) 31st January Evening Shift Chemistry - Hydrocarbons Question 17 English Option 3
D
JEE Main 2024 (Online) 31st January Evening Shift Chemistry - Hydrocarbons Question 17 English Option 4
3
JEE Main 2024 (Online) 30th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Products A and B formed in the following set of reactions are

JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 13 English

A
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 13 English Option 1
B
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 13 English Option 2
C
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 13 English Option 3
D
JEE Main 2024 (Online) 30th January Evening Shift Chemistry - Hydrocarbons Question 13 English Option 4
4
JEE Main 2024 (Online) 30th January Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Compound A formed in the following reaction reacts with B gives the product C. Find out A and B.

JEE Main 2024 (Online) 30th January Morning Shift Chemistry - Hydrocarbons Question 12 English

A
$$\mathrm{A}=\mathrm{CH}_3-\mathrm{C} \equiv \stackrel{-}{\mathrm{C}} \mathrm{Na}^{+}, \mathrm{B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}$$
B
$$\mathrm{A}=\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2, \mathrm{~B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}$$
C
$$\mathrm{A}=\mathrm{CH}_3-\mathrm{C} \equiv \stackrel{-}{\mathrm{C}} \mathrm{Na}^{+}, \mathrm{B}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3$$
D
$$\mathrm{A}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3, \mathrm{~B}=\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$$
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