1
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A cell of internal resistance r drives current through an external resistance R. The power delivered by the cell to the external resistance will be maximum when :-
A
R = 1000 r
B
R = r
C
R = 2r
D
R = 0.001 r
2
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
In the figure shown, what is the current (in Ampere) drawn from the battery ?
You are given: R1 = 15$$\Omega $$, R2 = 10 $$\Omega $$, R3 = 20 $$\Omega $$, R4 = 5$$\Omega $$, R5 = 25$$\Omega $$, R6 = 30 $$\Omega $$, E = 15 V JEE Main 2019 (Online) 8th April Evening Slot Physics - Current Electricity Question 234 English
A
13/24
B
7/18
C
9/32
D
20/3
3
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
A 200 $$\Omega $$ resistor has a certain color code. If one replaces the red color by green in the code, the new resistance will be :
A
500 $$\Omega $$
B
100 $$\Omega $$
C
200 $$\Omega $$
D
300 $$\Omega $$
4
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the circuit shown, with R1 = 1.0W, R2 = 2.0 W, E1 = 2 V and E2 = E3 = 4 V, the potential difference between the points 'a' and 'b' is approximately (in V): JEE Main 2019 (Online) 8th April Morning Slot Physics - Current Electricity Question 237 English
A
3.3
B
2.7
C
2.3
D
3.7
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