1
JEE Main 2017 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
JEE Main 2017 (Offline) Physics - Current Electricity Question 282 English
In the given circuit, the current in each resistance is:
A
0 A
B
1 A
C
0.25 A
D
0.5 A
2
JEE Main 2017 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
When a current of 5 mA is passed through a galvanometer having a coil of resistance 15$$\Omega $$, it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 0 – 10V is:
A
4.005 × 103 $$\Omega $$
B
1.985 × 103 $$\Omega $$
C
2.535 × 103 $$\Omega $$
D
2.045 × 103 $$\Omega $$
3
JEE Main 2016 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A galvanometer has a 50 division scale. Battery has no internal resistance. It is found that there is deflection of 40 divisions when R = 2400 $$\Omega $$. Deflection becomes 20 divisions when resistance taken from resistance box is 4900 $$\Omega $$. Then we can conclude :

JEE Main 2016 (Online) 10th April Morning Slot Physics - Current Electricity Question 263 English
A
Resistance of galvanometer is 200 $$\Omega $$
B
Full scale deflection current is 2 mA.
C
Current sensitivity of galvanometer is 20 $$\mu $$A/division.
D
Resistance required on R.B. for a deflection of 10 divisions is 9800 $$\Omega $$.
4
JEE Main 2016 (Online) 10th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The resistance of an electrical toaster has a temperature dependence given by R(T) = R0 [1 + $$\alpha $$(T − T0)] in its range of operation. At T0 = 300 K, R = 100 $$\Omega $$ and at T = 500 K, R = 120 $$\Omega $$. The toaster is connected to a voltage source at 200 V and its temperature is raised at a constant rate from 300 to 500 K in 30 s. The total work done in raising the temperature is :
A
400 $$\ln \,{{1.5} \over {1.3}}\,J$$
B
200 $$\ln \,{{2} \over {3}}\,J$$
C
60000 $$\ln \,{{6} \over {5}}\,J$$
D
300 J
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